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katovenus [111]
3 years ago
8

0.001 is 1/10 the value of?

Mathematics
2 answers:
tamaranim1 [39]3 years ago
7 0

Answer:

0.01

Step-by-step explanation:

DaniilM [7]3 years ago
5 0
No it is not it would be 1.0
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The length of the sides of a triangle are 2x +y/2, 5x/3+y + ½ and 2/3x +2y +5/2. If the triangle is equilateral, find its perime
Sav [38]

Answer:

Step-by-step explanation:

If the triangle is equilateral :

2x +y/2 =  5x/3+y + ½  = 2/3x +2y +5/2

so the perimeter is : P = 3(2x +y/2) or 3(5x/3+y + ½) or 3(2/3x +2y +5/2)

the simplest is :  P = 3(2x +y/2)

                            P = 6x + (3y)/2

6 0
3 years ago
In a 51-inch television, the length of the screen's diagonal is 51 inches. If the screen's height is 25 inches,
DaniilM [7]

Answer:

44.452

Step-by-step explanation:

Using the Pythagorean theorem you can use:

51^2 = 25^2 + w^2

2601 = 625 +w^2

w^2 = 1976

w = 44.452

6 0
2 years ago
Read 2 more answers
If one yard equals 3 ft in one mile equals 5280 ft how many yards are there in 2 miles
Georgia [21]

Answer:

2 miles = 3520 yards

Step-by-step explanation:

1 mile = 1760 yards

2 miles = 3520 yards

5 0
3 years ago
A) How many ways can 2 integers from 1,2,...,100 be selected
Anna007 [38]

Answer with explanation:

→Number of Integers from 1 to 100

                                            =100(50 Odd +50 Even)

→50 Even =2,4,6,8,10,12,14,16,...............................100

→50 Odd=1,3,,5,7,9,..................................99.

→Sum of Two even integers is even.

→Sum of two odd Integers is odd.

→Sum of an Odd and even Integer is Odd.

(a)

Number of ways of Selecting 2 integers from 50 Integers ,so that their sum is even,

   =Selecting 2 Even integers from 50 Even Integers , and Selecting 2 Odd integers from 50 Odd integers ,as Order of arrangement is not Important, ,

        =_{2}^{50}\textrm{C}+_{2}^{50}\textrm{C}\\\\=\frac{50!}{(50-2)!(2!)}+\frac{50!}{(50-2)!(2!)}\\\\=\frac{50!}{48!\times 2!}+\frac{50!}{48!\times 2!}\\\\=\frac{50 \times 49}{2}+\frac{50 \times 49}{2}\\\\=1225+1225\\\\=2450

=4900 ways

(b)

Number of ways of Selecting 2 integers from 100 Integers ,so that their sum is Odd,

   =Selecting 1 even integer from 50 Integers, and 1 Odd integer from 50 Odd integers, as Order of arrangement is not Important,

        =_{1}^{50}\textrm{C}\times _{1}^{50}\textrm{C}\\\\=\frac{50!}{(50-1)!(1!)} \times \frac{50!}{(50-1)!(1!)}\\\\=\frac{50!}{49!\times 1!}\times \frac{50!}{49!\times 1!}\\\\=50\times 50\\\\=2500

=2500 ways

7 0
3 years ago
There are 3 quarters, 4 dimes and 7 nickels in a change purse. Suppose 3 coins are selected without replacement. What is the pro
qwelly [4]
Prob of just quarter is 3/14 for a dime is 4/14 and for a nickel its 7/14
then all you do is multiply them all together to get 306122449/<span>10000000000 that took me way to long</span>
6 0
3 years ago
Read 2 more answers
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