Each must sell 35,678 dollars each year not counting commision to add 6 percent of that.
Answer:
42.43
Step-by-step explanation:
Given:
A circle with a radius of 5 cm sits inside a 11 cm x 11 cm rectangle.
Question asked:
What is the area of the shaded region as shown in the figure ?
Solution:
First of all calculate area of circle and then area of rectangle:-


<u>As here length an width both are 11 cm, we can say that this is a square.</u>
<u />

Now, area of shaded region = Area of square - Area of circle
= 121 - 78.571 = 42.429 
Therefore, the area of the shaded region will be 42.43 
Answer:
It's the b graph
Step-by-step explanation:
Khan Academy.
Check the picture below.
so we know the radius of the semicircle is 2 and the rectangle below it is really a 4x4 square, so let's just get their separate areas and add them up.
![\stackrel{\textit{area of the semicircle}}{\cfrac{1}{2}\pi r^2}\implies \cfrac{1}{2}(\stackrel{\pi }{3.14})(2)^2\implies 3.14\cdot 2\implies 6.28 \\\\\\ \stackrel{\textit{area of the square}}{(4)(4)}\implies 16 \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \stackrel{\textit{sum of both areas}}{16+6.28=22.28}~\hfill](https://tex.z-dn.net/?f=%5Cstackrel%7B%5Ctextit%7Barea%20of%20the%20semicircle%7D%7D%7B%5Ccfrac%7B1%7D%7B2%7D%5Cpi%20r%5E2%7D%5Cimplies%20%5Ccfrac%7B1%7D%7B2%7D%28%5Cstackrel%7B%5Cpi%20%7D%7B3.14%7D%29%282%29%5E2%5Cimplies%203.14%5Ccdot%202%5Cimplies%206.28%20%5C%5C%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7Barea%20of%20the%20square%7D%7D%7B%284%29%284%29%7D%5Cimplies%2016%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20~%5Chfill%20%5Cstackrel%7B%5Ctextit%7Bsum%20of%20both%20areas%7D%7D%7B16%2B6.28%3D22.28%7D~%5Chfill)
There are 6 numbers on each die.
The total number of out comes is 6 x 6 = 36.
To get a sum of 4, the combinations are: 1 & 3, 2 & 2 or 3 & 1.
To get a sum of 8, the combinations are: 1 & 7, 2 & 6, 3 & 5, 4 & 4, 7 & 1, 6 & 2, 5 & 3
The total of those combinations are: 3 + 7 = 10 total combinations of a sum of either 4 or 8.
The probability of either is 10/36, which can be reduced to 5/18.