Answer:
Most people found the probability of just stopping at the first light and the probability of just stopping at the second light and added them together. I'm just going to show another valid way to solve this problem. You can solve these kinds of problems whichever way you prefer.
There are three possibilities we need to consider:
Being stopped at both lights
Being stopped at neither light
Being stopped at exactly one light
The sum of the probabilities of all of the events has to be 1 because there is a 100% chance that one of these possibilities has to occur, so the probability of being stopped at exactly one light is 1 minus the probability of being stopped at both lights minus the probability of being stopped at neither.
Because the lights are independent, the probability of being stopped at both lights is just the probability of being stopped at the first light times the probability of being stopped at the second light. (0.4)(0.7) = 0.28
The probability of being stopped at neither is the probability of not being stopped at the first light, which is 1-0.4 or 0.6, times the probability of not being stopped at the second light, which is 1-0.7 or 0.3. (0.6)(0.3) = 0.18
Step-by-step explanation:
4 sticks of butter to make 4 batches of lemon bars
2 times, you can fold it without no overlapping on any line
one would say that the simple interest doubles if the period of time is specified in the contract and the contract is still valid, if the interest amount is available anitime and so on.
So if the amount doubles let's say at half time for which the principal was awarded to the bank, by the end of the contract , the interest amount can be double × just increased by 1.5
The answer is B) 20 lbs for $22 because carol is getting 8 pounds more for only $9+