Answer:
They will do rounds together again in 11 minutes and 40 seconds.
Step-by-step explanation:
Security A rounds every 2 minutes and 20 seconds in the gate 1.
That is, after 2*60 + 20 = 120 + 20 = 140 seconds.
Security B rounds every 1 minute and 40 seconds in the gate 2.
That is, after 1*60 + 40 = 60 + 40 = 100 seconds.
After how many minutes they will rounds together again?
First, we find this is seconds, which is the least common multiple between 140 and 100. Factoring them by prime factors:
140 - 100|2
70 - 50|2
35 - 25|5
7 - 5|5
7 - 1|7
1 - 1
lcm(140,100) = 2*2*5*5*7 = 700 seconds
They will do rounds together again in 700 seconds, which is 11 minutes and 40 seconds.
a) The students who are members of both sets can be described by
... a ∩ b
b) The students who are members of a but not b can be described by
... a ∩ b'
c) The students who are members of one or both sets can be described by
... a ∪ b
d) The students who are not in one set or not in the other set can be described by
... a' ∪ b' . . . . = (a ∩ b)'
Answer:
Ans = B
Step-by-step explanation:
The answer is B
Have a great day
