Answer:
Divide by 2
q^2+4q=3/2
q^2+4q(4/2)^2=3/2+(4/2)^2
(q+4/2)^2=3/2+16/4
taking the square root of both side
√(q+4/2)^2=√(3/2+16/4)
Note that the square will cancel the square root then you will take LCM on the right hand side
q+4/2=√6+16/4
q+4/2=√22/4
q= -4/2+-√22/4
q=(-4+_√22/4)
Answer:
The range of a relation is the set of the second coordinates from the ordered pairs.
Step-by-step explanation:
The range of a relation from A to B is a subset of B. For Example: If A = {2, 4, 6, 8) B = {5, 7, 1, 9}. Let R be the relation 'is less than' from A to B.
Answer is 1704 and to explain just put that you added to get your final answer
6. 6 x 6 x 6 = 216 so 6^3 is 216
