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DerKrebs [107]
2 years ago
5

Mark has a container that looks like a cube. He uses 64 cubes with side lengths of 1 inch to completely fill the container. what

s the length of the container?
Mathematics
2 answers:
sp2606 [1]2 years ago
5 0

Answer:

4 inches. if the volume is 64, then the length, width, and height are all 4 inches. 4 x 4 x 4 = 64. hope this helps

Step-by-step explanation:

- Zombie

kow [346]2 years ago
4 0

Answer:

64 inches from what i am reading

Step-by-step explanation:

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Please answer the circled questions below!
Anton [14]

Answer:

Step-by-step explanation:

1. The y-values in the table are constant, so the slope is 0. It is a horizontal line.

There is no x-intercept.

The y-intercept is (0, 1).

__

For lines in standard form, the intercepts can be found easily. The x-intercept is the value of x when y=0:

  ax +0 = c

  x = c/a . . . . x-intercept

Similarly, the y-intercept is the value of y when x=0:

  0 +by = c

  y = c/b

__

3. x-intercept = (-20/2, 0) = (-10, 0)

  y-intercept = (0, -20/-5) = (0, 4)

__

4. x-intercept = (-6/1, 0) = (-6, 0)

  y-intercept = (0, -6/-3) = (0, 2)

Plot these points and draw a line through them.

8 0
3 years ago
Find the common ratio r for the given geometric sequence and find the next three terms.
34kurt

Answer:

The common ratio is -2

Next three terms are 18, -36, and 72

Step-by-step explanation:

The common ratio is -2 since each consecutive term is being multiplied by -2

The next three terms are -9(-2) = 18, 18(-2) = -36, and -36(-2) = 72

4 0
2 years ago
Read 2 more answers
Factor 2m^3-12m^2+18m completely
Nina [5.8K]

Answer:

The answer is A.

Step-by-step explanation:

Firstly, you have to take out the common terms for this expression. In this expression, the common terms ard 2 and m :

2 {m}^{3}  - 12 {m}^{2}  + 18m

= 2( {m}^{3}  - 6 {m}^{2}  + 9m)

= 2m( {m}^{2}  - 6m + 9)

Next you have to factorise the brackets :

{m}^{2}  - 6m + 9

=  {m}^{2}  - 3m - 3m + 9

= m(m - 3) - 3(m - 3)

= (m - 3)(m - 3)

=  {(m - 3)}^{2}

So the final answer is :

2m {(m - 2)}^{2}

6 0
3 years ago
Read 2 more answers
In a statistics class, students were asked how many siblings they have. The mean number of siblings for the class is 3.08 with a
Rom4ik [11]

Answer:

A

Step-by-step explanation:

YEAH BOY

5 0
2 years ago
Prove that if x is an positive real number such that x + x^-1 is an integer, then x^3 + x^-3 is an integer as well.
Shkiper50 [21]

Answer:

By closure property of multiplication and addition of integers,

If x + \dfrac{1}{x} is an integer

∴ \left ( x + \dfrac{1}{x} \right) ^3 = x^3 + \dfrac{1}{x^3} +3\cdot \left (x + \dfrac{1}{x} \right ) is an integer

From which we have;

x^3 + \dfrac{1}{x^3} is an integer

Step-by-step explanation:

The given expression for the positive integer is x + x⁻¹

The given expression can be written as follows;

x + \dfrac{1}{x}

By finding the given expression raised to the power 3, sing Wolfram Alpha online, we we have;

\left ( x + \dfrac{1}{x} \right) ^3 = x^3 + \dfrac{1}{x^3} +3\cdot x + \dfrac{3}{x}

By simplification of the cube of the given integer expressions, we have;

\left ( x + \dfrac{1}{x} \right) ^3 = x^3 + \dfrac{1}{x^3} +3\cdot \left (x + \dfrac{1}{x} \right )

Therefore, we have;

\left ( x + \dfrac{1}{x} \right) ^3 - 3\cdot \left (x + \dfrac{1}{x} \right )= x^3 + \dfrac{1}{x^3}

By rearranging, we get;

x^3 + \dfrac{1}{x^3} = \left ( x + \dfrac{1}{x} \right) ^3 - 3\cdot \left (x + \dfrac{1}{x} \right )

Given that  x + \dfrac{1}{x} is an integer, from the closure property, the product of two integers is always an integer, we have;

\left ( x + \dfrac{1}{x} \right) ^3 is an integer and 3\cdot \left (x + \dfrac{1}{x} \right ) is also an integer

Similarly the sum of two integers is always an integer, we have;

\left ( x + \dfrac{1}{x} \right) ^3 + \left(- 3\cdot \left (x + \dfrac{1}{x} \right ) \right  ) is an integer

\therefore x^3 + \dfrac{1}{x^3} =   \left ( x + \dfrac{1}{x} \right) ^3 - 3\cdot \left (x + \dfrac{1}{x} \right )= \left ( x + \dfrac{1}{x} \right) ^3 + \left(- 3\cdot \left (x + \dfrac{1}{x} \right ) \right  ) is an integer

From which we have;

x^3 + \dfrac{1}{x^3} is an integer.

4 0
3 years ago
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