Let's compare apples to apples and oranges to oranges: convert each given proper fraction into its decimal counterpart:
3 63/80 => 3 .788 approx.
3 1/5 => 3.2
3 11/20 => 3.55
It's now an easy matter to arrange these numbers from least to greatest:
3.2, 3.55, 3.79, or
3 1/5, 3 11/20, 3 63/80
Answer:
0.36878
Step-by-step explanation:
Given that:
Mean number of miles (m) = 2135 miles
Variance = 145924
Sample size (n) = 40
Standard deviation (s) = √variance = √145924 = 382
probability that the mean of a sample of 40 cars would differ from the population mean by less than 29 miles
P( 2135 - 29 < z < 2135 + 29)
Z = (x - m) / s /√n
Z = [(2106 - 2135) / 382 / √40] < z < [(2164 - 2135) / 382 / √40]
Z = (- 29 / 60.399503) < z < (29 / 60.399503)
Z = - 0.4801364 < z < 0.4801364
P(Z < - 0.48) = 0.31561
P(Z < - 0.48) = 0.68439
P(- 0.480 < z < 0.480) = 0.68439 - 0.31561 = 0.36878
= 0.36878
For example, the three 2s.
in the box show that there are 3 groups of 2 objects each.You can write the multiplication equation 3 2 = 6 to show that 3 groups of 2 equals 6 in all.You can also write the division equation 6 2 = 3 to show that 6 divided into groups of 2 equals 3 groups.
The correct answer of the given question above would be 8ft/sec. The minimum speed that the stone be thrown so as to reach a height of 49 feet is 8ft/sec. Consider this given solution here:
u^2 = 2x a x 1
<span>u^2 = 2 x 32 x 1 </span>
<span>u = 8 ft/sec
</span>Hope this answer helps and this is what you are looking for.
Answer:
11 ft
Step-by-step explanation:
Given the two lengths of a triangle as
AB = 6ft
AC = 6ft
This is an isosceles triangle because only 2 sides are equal.
In an isosceles triangle, the sum of 2 (sides) lengths must be greater than the other length.
Therefore, let's assume the following:
i) AC + AB > BC
6 + 6 > BC
12 > BC (BC is less than 12)
BC < 12
ii) BC + AC > AB
BC + 6 > 6
BC > 6 - 6
BC > 0
Therefore the range of values for BC =
0 < BC < 12
Since BC must be bigger than one of the lengths and it must also be less than the sum of the 2 sides. The length of BC could be 11 because it is less than (6+6) 12 and greater than 6.
