<em>So</em><em> </em><em>the</em><em> </em><em>right</em><em> </em><em>answer</em><em> </em><em>is</em><em> </em><em>1</em><em>.</em><em>8</em>
<em>Look </em><em>at</em><em> the</em><em> </em><em>attached</em><em> </em><em>picture</em>
<em>Hope</em><em> </em><em>it</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>you</em>
<em>Good</em><em> </em><em>luck</em><em> </em><em>on</em><em> </em><em>your</em><em> </em><em>assignment</em>
Let's start with the smallest prime number 2
60/2 = 30
Divide that result over 2
30/2 = 15
We can't divide this by 2 because 15/2 = 7.5 isn't a whole number
Let's move onto 3
15/3 = 5
The result is a prime number, so we stop.
The values we divided as denominators were: {2, 2, 3}
We add the result 5 to the set to completely list all of the prime factors of 60
The prime factorization would be
<h3>60 = 2*2*3*5</h3>
which is the same as saying
<h3>60 = 2^2*3*5</h3>
Answer:
1 for all evaluate questions
Step-by-step explanation:
just remember anything to the zero power is 1
Answer:
- sum: 3x² -4x -4
- product: (x -2)(3x +2)
Step-by-step explanation:
The areas of four regions are given. We can simply add them to find the sum. To express them as a product, we need to look at common factors.
<h3>Sum</h3>
The total of the given area expressions is ...
3x² +2x -6x -4 = 3x² -4x -4 . . . . sum
<h3>Product</h3>
Extending the table to show common factors of each row and column, we have ...

Since each cell of the table is the product of the corresponding common factors, we can write the area as the product ...
(x -2)(3x +2) . . . . product
I gotchu my guy let me know what you need help with I’d gladly revive those free points