Which of the following is a geometric series?

Mathematics

2 answers:

seraphim [82]3 years ago

7 0

Answer:

D: 2+14+98+686

Step-by-step explanation:

Correct on edge quiz.

lions [1.4K]3 years ago

3 0

Answer:

Answer is D

Step-by-step explanation:

Got 100%

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Solve for x. X + 5 = 2x OX=3 OX=-3 OX=-5 Ox=5

Alisiya [41]

Isolate the variable by dividing each side by factors that don't contain the variable.
X = 5

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4 years ago

A line that includes the points (-1,8) and (1,6) what is the equation in point slope form

Delicious77 [7]

Step-by-step explanation:

6-8/1- -1 = -2/2 = -1 is the slope

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3 years ago

Find maclaurin series

Mumz [18]

Recall the Maclaurin expansion for cos(x), valid for all real x :

$\displaystyle \cos(x) = \sum_{n=0}^\infty (-1)^n \frac{x^{2n}}{(2n)!}$

Then replacing x with √5 x (I'm assuming you mean √5 times x, and not √(5x)) gives

$\displaystyle \cos\left(\sqrt 5\,x\right) = \sum_{n=0}^\infty (-1)^n \frac{\left(\sqrt5\,x\right)^{2n}}{(2n)!} = \sum_{n=0}^\infty (-5)^n \frac{x^{2n}}{(2n)!}$

The first 3 terms of the series are

$\cos\left(\sqrt5\,x\right) \approx 1 - \dfrac{5x^2}2 + \dfrac{25x^4}{24}$

and the general n-th term is as shown in the series.

In case you did mean cos(√(5x)), we would instead end up with

$\displaystyle \cos\left(\sqrt{5x}\right) = \sum_{n=0}^\infty (-1)^n \frac{\left(\sqrt{5x}\right)^{2n}}{(2n)!} = \sum_{n=0}^\infty (-5)^n \frac{x^n}{(2n)!}$