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Natalija [7]
2 years ago
13

HELP IM GOING TO HAVE A MENTAL BREAKDOWN

Mathematics
1 answer:
Marysya12 [62]2 years ago
3 0

Answer:

x = 3 ; y=2

Step-by-step explanation:

to simplify the work we can build a system of two equations

2x+3 = 3y+3

x = y+1

we can now substitute the value of x in the first equation

2(y+1)+3 = 3y+3

2y + 2 + 3 = 3y+3

2y + 5 = 3y+3

y = 2

now we can subisitute the value of y in the first equation

x = 2 + 1 = 3

Verify

2(3)+3 = 6+3 = 9

3(2) + 3 = 6 + 3 = 9

3

2+1 = 3

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The indefinite integral will be  \int (7x^2+8x-2)dx=\dfrac{7x^3}{3}+4x^2-2x+C)

<h3 /><h3>what is indefinite integral?</h3>

When we integrate any function without the limits then it will be an indefinite integral.

General Formulas and Concepts:

Integration Rule [Reverse Power Rule]:                                                              

\int x^ndx=\dfrac{x^{n+1}}{n+1}}+C

Integration Property [Multiplied Constant]:                                                        

\int cf(x)dx=c\int f(x)dx

Integration Property [Addition/Subtraction]:                                                      

\int [f(x)\pmg(x)]dx=\int f(x)dx\pm \intg(x)dx

[Integral] Rewrite [Integration Property - Addition/Subtraction]:

\int (7x^2+8x-2)dx=\int 7x^2dx+\int 8xdx    -\int 2dx          

[Integrals] Rewrite [Integration Property - Multiplied Constant]:  

\int (7x^2+8x-2)dx=7 \int x^2dx+ 8 \int xdx    -2\int dx            

[Integrals] Reverse Power Rule:    

\int (7x^2+8x-2)dx= 7(\dfrac{x^3}{3})+8(\dfrac{x^2}{2})-2x+C                                                            

Simplify:    

\int (7x^2+8x-2)dx= \dfrac{7x^3}{3}+4x^2-2x+C                                                                                                      

So the indefinite integral will be \int (7x^2+8x-2)dx= \dfrac{7x^3}{3}+4x^2-2x+C                

To know more about indefinite integral follow

brainly.com/question/27419605

#SPJ4

7 0
2 years ago
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