The answer would be 1.2/7
Answer:
3/4
Step-by-step explanation:
15/20=3/4 if you divide both sides by 5
Answer: a - 4.512 hours
b - 1.94 hours
Step-by-step explanation:
Given,
a) A(t) = 10 (0.7)^t
To determine when 2mg is left in the body
We would have,
A(t) = 2, therefore
2 = 10(0.7)^t
0.7^t =2÷10
0.7^t = 0.2
Take the log of both sides,
Log (0.7)^t = log 0.2
t log 0.7 = log 0.2
t = log 0.2/ 0.7
t = 4.512 hours
Thus it will take 4.512 hours for 2mg to be left in the body.
b) Half life
Let A(t) = 1/2 A(0)
Thus,
1/2 A(0) = A(0)0.7^t
Divide both sides by A(0)
1/2 = 0.7^t
0.7^t = 0.5
Take log of both sides
Log 0.7^t = log 0.5
t log 0.7 = log 0.5
t = log 0.5/log 0.7
t = 1.94 hours
Therefore, the half life of the drug is 1.94 hours
Answer:
Quinn can expect to pick blue 40 times
Step-by-step explanation:
the probability of picking blue is stated as 2/10 which can be reduced to 1/5
multiply the number of times they pick a marble ( shown as 200) by the probability of picking a blue one ( 1/5)
200 x 1/5 = 200 / 5 = 40
Quinn can expect to pick blue 40 times
