angle T would be half the arc length of RQ
118/2 = 59
angle T = 59 degrees
Answer:
a) NORM.S.INV(0.975)
Step-by-step explanation:
1) Some definitions
The standard normal distribution is a particular case of the normal distribution. The parameters for this distribution are: the mean is zero and the standard deviation of one. The random variable for this distribution is called Z score or Z value.
NORM.S.INV Excel function "is used to find out or to calculate the inverse normal cumulative distribution for a given probability value"
The function returns the inverse of the standard normal cumulative distribution(a z value). Since uses the normal standard distribution by default the mean is zero and the standard deviation is one.
2) Solution for the problem
Based on this definition and analyzing the question :"Which of the following functions computes a value such that 2.5% of the area under the standard normal distribution lies in the upper tail defined by this value?".
We are looking for a Z value that accumulates 0.975 or 0.975% of the area on the left and by properties since the total area below the curve of any probability distribution is 1, then the area to the right of this value would be 0.025 or 2.5%.
So for this case the correct function to use is: NORM.S.INV(0.975)
And the result after use this function is 1.96. And we can check the answer if we look the picture attached.
Answer:
3
Step-by-step explanation:
The answer is D because 3 can’t go to different numbers on the x column
Hello there!
My best guess would be to plug in 5 into n.
So:
f (n) = 5n-2
f (5) = 5 (5) -2
f (5) = 25-2
f (5) = 23
This is my GUESS. I'm not sure how to do this problem (it's been a while since I've done this).
So PLEASE get a second opinion or ask a teacher!
Hope this helped!
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