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denis-greek [22]
3 years ago
11

HELP what are the coefficients of 7x^4-9x^3+2x^2

Mathematics
1 answer:
Nikitich [7]3 years ago
6 0

In this case, whenever you see a number directly in front of x, multiplying itself by/with x, it's a coefficient.

That applies to the numbers 7, 9, and 2 if I'm reading this correctly. Hope this helps!

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AURORKA [14]

Answer:

d

Step-by-step explanation:

Using the Cosine rule to find ∠ A

cosA = \frac{b^2+c^2-a^2}{2bc}

         = \frac{5.1^2+5.7^2-7.3^2}{2(5.1)(5.7)}

         = \frac{26.01+32.49-53.29}{58.14}

         = \frac{5.21}{58.14} , then

∠ A = cos^{-1} ( \frac{5.21}{58.14} ) ≈ 84.9° ( to 1 dec. place )

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what is the equation, in slope- intercept form, of the line that contains the points (-3,4) and (5,7)
gavmur [86]

Answer:

y = \frac{3}{8} x + \frac{41}{8}

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y-intercept )

To calculate the slope use the gradient formula

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = (- 3, 4) and (x₂, y₂ ) = (5, 7)

m = \frac{7-4}{5+3} = \frac{3}{8}, hence

y = \frac{3}{8} x + c ← is the partial equation

To find c substitute either of the 2 points into the partial equation

using (5, 7 ), then

7 = \frac{15}{8} + c ⇒ c = 7 - \frac{15}{8} = \frac{41}{8}

y = \frac{3}{8} x + \frac{41}{8} ← equation in slope-intercept form


6 0
3 years ago
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