(13/3)^3 or (13/3)•(13/3)•(13/3)
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Greetings from Brasil...
Let's apply the given formula:
A = (1/2)·B·H
The base of this polygon (in this case, the triangle) is B
B = X² - 2X + 6
The height of this polygon is H and is H
H = X + 4
Applying these values (B and H) in the given formula.....
A = (1/2)·B·H
A = (1/2)·(X² - 2X + 6)·(X + 4)
A = (1/2)·(X³ + 2X² - 2X + 24)
A = (X³/2) + X² - X + 12
OR
A = (X³ + 2X² - 2X + 24)/2
Answer:
x= 3
Step-by-step explanation:
4x+ 4 x= 12 + 12
8x = 24
x= 24/8
x= 3
Answer: x = 6.32 or -0.32
Step-by-step explanation:
2x² - 6x + 10 = 0
No we divide the expression by 2 to make the coefficient of x² equals 1
We now have
x² - 3x + 5 = 0
Now we remove 5 to the other side of the equation
x² - 3x = -5
we add to both side square of half the coefficient of x which is 3
x² - 3x + ( ⁻³/₂)² = -5 + (⁻³/₂)²
(x - ³/₂)² = -5 + ⁹/₄
Resolve into fraction
(x - ³/₂)² = ⁻¹¹/4
Take the roots of the equation
x - ³/₂ = √¹¹/₄
x - ³/₂ = √11/₂
x = ³/₂ ± 3.32/₂
= 3+ 3.32 or 3 - 3.32
= 6.32 or - 0.32
