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Answer:
The probability that between 79% and 81%of the 500 sampled wildlife watchers actively observed mammals in 2011 is P=0.412.
Step-by-step explanation:
We know the population proportion π=0.8, according to the 2011 National Survey of Fishing, Hunting, and Wildlife-Associated Recreation.
If we take a sample from this population, and assuming the proportion is correct, it is expected that the sample's proportion to be equal to the population's proportion.
The standard deviation of the sample is equal to:

With the mean and the standard deviaion of the sample, we can calculate the z-value for 0.79 and 0.81:

Then, the probability that between 79% and 81%of the 500 sampled wildlife watchers actively observed mammals in 2011 is:

Answer:
0.08 pounds per pint.
Step-by-step explanation:
Given: The density of a certain material is such that it weighs 10 ounces per gallon.
We are to express this density in pounds per pint.
1 gallon ⇒ 10 ounces
1 pound = 16 ounces
How many pounds? = 10 ounces.
Cross-multiplying gives;
pounds
1 gallon = 8 pints
The density in pounds per pint is;
0.625 pounds ÷ 8 pints = 0.078125 pounds per pint = 0.08 pounds per pint (answer rounded up to the nearest hundredth).
8 inches......................
Answer:
c the 3rd one
Step-by-step explanation:
hope this helps you.