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svetlana [45]
3 years ago
11

Tristan bought school supplies. He bought a

Mathematics
1 answer:
ra1l [238]3 years ago
5 0

Answer: he bought 5 binders in total (sry if it’s wrong)

Step-by-step explanation:

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Ad libitum [116K]
Rounded it would be 2.91
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What is the z-score of a value that is 2.08 standard deviations greater than the mean?
Nuetrik [128]
The question is asking to states the value of the z-score of a value that is 2.08 standard deviations greater than the mean and base on my research, the possible answer would be z-score is the number of standard deviations above the mean. <span>If you are 5 standard deviations above the mean, that is defined as z = 5. </span><span>If you are 1.1 standard deviations above the mean, that is defined as z = 1.1. </span>
<span>And so if you are 2.08 standard deviations above the mean</span>
6 0
3 years ago
Find the product of the expression:<br> (5p^3) (-1m^8p^2)
Rainbow [258]

Answer:

We conclude that:

  • \left(5p^3\right)\:\left(-1m^8p^2\right)=-5p^5m^8

Step-by-step explanation:

Given the expression

\left(5p^3\right)\:\left(-1m^8p^2\right)

Apply the rule:

a\left(-b\right)=-ab

so the expression becomes

\left(5p^3\right)\left(-1\cdot \:m^8p^2\right)=-5p^3\cdot \:1\cdot \:m^8p^2

Apply the rule:

a^b\cdot \:a^c=a^{b+c}

so the expression becomes

                             =-5p^{3+2}\cdot \:1\cdot \:m^8         ∵ p^3p^2=p^{3+2}

                             =-5p^5\cdot \:1\cdot \:m^8

                             =-5p^5m^8

Therefore, we conclude that:

  • \left(5p^3\right)\:\left(-1m^8p^2\right)=-5p^5m^8
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2 years ago
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Answer:

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Step-by-step explanation:

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Triangle ABC is the pre-image and triangle DFE is the image.
anzhelika [568]

Answer:

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Step-by-step explanation:

The original image is the preimage = ∆ACB

The new image is the image = ∆DFE

The scale of factor of dilation = image/preimage = DF/AC

DF = 6 cm (given)

AC = 12 cm (given)

Plug in the values into the equation to find the scale factor of dilation:

Scale factor = 6/12

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