If an algorithm created to help make hiring decisions is based on previous unfair decisions, then the algorithm may be flawed.
<h3>What are algorithms being used for?</h3>
Algorithms are known to be tools that are made to help in calculation, data processing, and a kind of automated reasoning.
Hence, If an algorithm created to help make hiring decisions is based on previous unfair decisions, then the algorithm may be flawed.
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Electro magnetism theory cover the basic principle of electro magnetism : experimental basis.
Electromagnetism is defined as an attraction between two partical.
Answer:
The function declaration to this question as follows:
Function declaration:
//declaring method printFeetInchShort, that accepts two integer parameters
void printFeetInchShort(int numFeet,int numInches) //method
{//method body
printf("The given height is: "); // message printing
printf("%d\'%d\" ", numFeet,numInches); //value printing
}
Explanation:
In the above method (function) declaration a method "printFeetInchShort" is declared, that accepts two integer variable as its parameters.
- This method uses a return type void, which means it will not return any value.
- The parameter "numFeet and numInches" accepts an integer value in the main method and inside the method, it will print its value by a single and double quote.
Answer:
def sum_cubes(n):
if n == 1:
return 1
else:
return n * n * n + sum_cubes(n-1)
print(sum_cubes(3))
Explanation:
Create a function called sum_cubes that takes one parameter, n
If n is equal to 1, return 1. Otherwise, calculate the cube of n, and add it to the sum_cubes function with parameter n-1
If we want to calculate the cubes of the first 3 numbers:
sum_cubes(3) = 3*3*3 + sum_cubes(2)
sum_cubes(2) = 2*2*2 + sum_cubes(1)
sum_cubes(1) = 1
If you substitute the values from the bottom, you get 27+8+1 = 36
Answer:
Explanation:
The following is written in Java and prints out the pattern to and from the first num parameter that is passed to the function. Meaning it goes from num1 to 0 and then from 0 to num1 again. It prints all of the values in a single line seperated by a space and a test case was used using the values provided in the question. The output can be seen in the attached picture below.
static void printNumPattern(int n1,int n2){
System.out.print(n1 + " ");
if(n1<=0) {
return;
} else {
printNumPattern(n1-n2,n2);
}
System.out.print(n1 + " ");
}
