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Anettt [7]
3 years ago
12

I think I have the correct answers but will anyone try to solve these questions so I can see if we got the same answer.

Mathematics
1 answer:
Andre45 [30]3 years ago
6 0

Because you seem to have an understanding of the material, I will write my math, but no explanations for my work. Comment on this answer for an explanation, or if I did something wrong.

1. Find the length of the South side of the field.

(5x+2)+(x^2-9)+(x^2-7x+12)\\5x+2+x^2-9+x^2-7x+12\\2x^2+5x+2-9-7x+12\\2x^2-2x+2-9+12\\2x^2-2x+5

2.Find the perimeter of the pumpkin field.

2(5x+2)+2(5x-2)\\(5x+2)+(5x+2)+(5x-2)+(5x-2)\\20x+4-4\\20x

3. Find the perimeter of the whole field.

2(4x+5x-2)+2(5x+2+x^2-9+x^2-7x+12)\\2(9x-2)+2(2x^2-2x-5)\\18x-4+4x^2-4x+10\\4x^2+14x+6

4. If x=30ft, what is the total perimeter?

P=4x^2+14x+6\\P=4(30)^2+14(30)+6\\P=4(900)+420+6\\P=1026ft

Random Tangent:

If you want to involve y in finding these answers for whatever reason, your math is going to get messy. Here's what I tried before I realized you could multiply each side by 2 to get the total perimeter:

xy+1+x+6=4x+5x-2\\xy-8x=-9\\x(y-8)=-9\\y-8=-\frac{9}{x}\\y=-\frac{9}{x}+8

Now the other side. This one's even worse.

xy-1+6x+x=5x+2+x^2-9+x^2-7x+12\\xy+9x-2x^2=5\\x(y+9+2x)=5\\2x+9+y=\frac{5}{x}\\y=\frac{5}{x}-2x-9

At this point, was realizing I wasn't going about the problem correctly, but did one last try by setting y=y. At this point in the equation, I simply had to stop, both due to complexity and technological problems.

\frac{5}{x}-2x-9=-\frac{9}{x}+8\\\frac{14}{x}=2x+17\\ 14=2x^2+17x\\0=2x^2+17x-13\\

I could possibly continue to solve, but I don't see a point. It was clear that this was NOT the right path to take finding the perimeter. It was here I realized that I could just multiply the two sides without y in them by 2 and--without as much difficulty--reach the correct answer.

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Which of these is NOT an integer
Tema [17]

Hi there!  

»»————- ★ ————-««

I believe your answer is:  

Option A

»»————- ★ ————-««  

Here’s why:  

⸻⸻⸻⸻

\boxed{\text{Option A:}}\\\\3^{-5}\\\\\rightarrow \frac{1}{3^5}\\\\\rightarrow  \frac{1}{243}\\\\\ \text{This is \textbf{NOT} an integer.}}

⸻⸻⸻⸻

\boxed{\text{Option B:}}\\\\-3^5\\\\\rightarrow -3 * -3 * -3 * -3 * -3 \\\\\rightarrow \boxed{-243}\\\\\\\text{This \textbf{IS} an integer.}

⸻⸻⸻⸻

\boxed{\text{Option C:}}\\\\\frac{1}{3}^{-5} \\\\\rightarrow \frac{1}{(\frac{1}{3})^5}\\\\\rightarrow \frac{1}{\frac{1}{243} }\\\\\rightarrow \boxed{243}\\\\\\\text{This \textbf{IS} an integer.}

⸻⸻⸻⸻

\text{Option \textbf{A} does not simplify into an integer.}

⸻⸻⸻⸻

»»————- ★ ————-««  

Hope this helps you. I apologize if it’s incorrect.  

7 0
3 years ago
Bella wants to save for a vacation in three years and this vacation costs $2300. She deposits $2000 into a bank earning 5% inter
ddd [48]

Answer:

$2,323.2

Step-by-step explanation:

A = P(1 + r/n)^nt

Where,

A = future value = ?

P = present value = 2,000

r = interest rate = 5% = 0.05

n = number of periods = 12

t = time = 3 years

A = P(1 + r/n)^nt

= 2,000(1 + 0.05/12)^12*3

= 2,000( 1 + 0.00417)^36

= 2,000( 1.00417)^36

= 2,000(1.1616)

= 2,323.2

A = $2,323.2

5 0
3 years ago
A random sample of size 100 was taken from a population. A 94% confidence interval to estimate the mean of the population was co
Free_Kalibri [48]

Answer: 1.88

Step-by-step explanation:

The confidence interval for population mean is given by :-

\mu\ \pm z_{\alpha/2}\dfrac{\sigma}{\sqrt{n}}

Given : Significance level : 1-0.94=0.06

Critical value : z_{\alpha/2}=z_{0.06/2}=z_{0.03}

By using the standard normal distribution table for z, we find the critical value of z_{0.03} corresponds to the p-value 0.03.

z_{0.03}=1.8807936\approx1.88

Hence, the z-value that was used in the computation must be 1.88 .

3 0
3 years ago
In a survey of 1000 randomly selected adults in the United States, participants were asked what their most favorite and what the
xenn [34]

Answer:

(a) The 95% confidence interval for the population proportion of US adults for whom math was their most favorite subject is (0.204, 0.256).

(b) The 95% confidence interval for the population proportion of US adults for whom math was their least favorite subject is (0.34, 0.40).

Step-by-step explanation:

The questions are:

(a) Construct and interpret a 95% confidence interval for the proportion of US adults for whom math was their most favorite subject.

(b) Construct and interpret a 95% confidence interval for the proportion of US adults for whom math was their least favorite subject. Solution:

(a)

The 95% confidence interval for the population proportion is:

CI=\hat p\pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}

Th information provided is:

<em>n</em> = 1000

Number of US adults for whom math was their most favorite subject

= <em>X</em>

= 230

Compute the sample proportion of US adults for whom math was their most favorite subject as follows:

\hat p=\frac{230}{1000}=0.23

The critical value of <em>z</em> for 95% confidence interval is:

z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96

Compute the 95% confidence interval for the population proportion of US adults for whom math was their most favorite subject as follows:

CI=\hat p\pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}

     =0.23\pm 1.96\sqrt{\frac{0.23(1-0.23)}{1000}}\\=0.23\pm 0.0261\\=(0.2039, 0.2561)\\\approx (0.204, 0.256)

Thus, the 95% confidence interval for the population proportion of US adults for whom math was their most favorite subject is (0.204, 0.256).

(b)

The 95% confidence interval for the population proportion is:

CI=\hat p\pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}

Th information provided is:

<em>n</em> = 1000

Number of US adults for whom math was their least favorite subject

= <em>X</em>

= 370

Compute the sample proportion of US adults for whom math was their least favorite subject as follows:

\hat p=\frac{370}{1000}=0.37

The critical value of <em>z</em> for 95% confidence interval is:

z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96

Compute the 95% confidence interval for the population proportion of US adults for whom math was their least favorite subject as follows:

CI=\hat p\pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}

     =0.37\pm 1.96\sqrt{\frac{0.37(1-0.37)}{1000}}\\=0.37\pm 0.0299\\=(0.3401, 0.3999)\\\approx (0.34, 0.40)

Thus, the 95% confidence interval for the population proportion of US adults for whom math was their least favorite subject is (0.34, 0.40).

8 0
3 years ago
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