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GenaCL600 [577]
3 years ago
9

What is the value of x?

Mathematics
2 answers:
ExtremeBDS [4]3 years ago
7 0

Answer:

X=75

Step-by-step explanation:

FD/DJ=SJ/YJ=FS/DY(BEING CORESSPONDING SIDE OF SIMILAR TRAINGLES)

TAKING FIRST AND SECOND RATIO

OR X/50=63/42

OR X*42=63*50

OR X=3150/42

OR X=75

Nataly [62]3 years ago
6 0

Answer:

x=75

Step-by-step explanation:

∆FSJ~∆DYJ

so the sides are proportional

SJ/YJ=FJ/DJ

(63+42)/42=(x+50)/50

105/42 ×50=x+50

125-50=x

x=75

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Help please and please no links
Naddik [55]
You answer is 152

Step by step:
Divide it into 2 rectangles
1st rectangle 10x8=80
2nd rectangle 12x6=72
80+72=152
7 0
3 years ago
Which of the following quadratic equations has no real solutions?
Virty [35]

Answer:

C. 3x^2 + 2x + 1

Step-by-step explanation:

A. 12^2 - (4*3*12) = 0 (there's one solution.)

B. (-3)^2 - (4*3*-18) = 255 (there're 2 real solutions.)

D. 3^2 - (4*0*-3) = 9 (there're 2 real solutions.)

C. 2^2 - (4*3*1) = -18 ✅✅

if b^2 - 4ac = negative then we can say that there isn't any real solution for the equation.

8 0
4 years ago
1. Jackie is a toll booth employee. One day, she wrote the expression: 0.75m = 15.75
Yanka [14]
Question B) you want to take 0.75, divide it to both sides and you get m= 21          0.75m=15.75      m =  21                                                                                     ___________  =                                                                                                          0.75             
4 0
4 years ago
4I-2I-I-3I please evaluate
Elena-2011 [213]
<span>4I-2I-I-3I
= 4(2) - 3
= 8 -3
= 5

hope it helps</span>
4 0
3 years ago
To get an estimate of consumer spending over a holiday season in 2009, 436 randomly sampled American adults were surveyed. Their
Tatiana [17]

Answer:

<em>-A 90% confidence interval would be narrower than the 95% confidence interval if we don't need to be as sure about our estimate. </em>

<em>-This confidence interval is not valid since the distribution of spending in the sample data is right skewed.</em>

<em>-The margin of error is $4.4.</em>

<em>-This confidence interval is valid since the sampling distribution of sample mean would be approximately normal with sample size of 436.</em>

<em>-We are 95% confident that the average spending of all American adults over this holiday season is between $80.31 and $89.11.</em>

<em />

Step-by-step explanation:

<em>A 90% confidence interval would be narrower than the 95% confidence interval if we don't need to be as sure about our estimate. </em>

TRUE. The 90% confidence is less strict in its probability of having the mean within the interval, so it is narrower than the 95% CI. It relies more in the information given by the sample.

<em />

<em>In order to decrease the margin of error of a 95% confidence interval to a third of what is is now, we would need to use a sample 3 times larger. </em>

FALSE. The margin of error is z*σ/(n^0.5). So to reduce it by two thirds, the sample size n needs to be 3^2=9 times larger.

<em>This confidence interval is not valid since the distribution of spending in the sample data is right skewed.</em>

FALSE. There is no information about the skewness in the sample.

<em>The margin of error is $4.4.</em>

TRUE. The margin of error is (89.11-80.31)/2=$4.4.

<em>We are 95% confident that the average spending of these 435 American adults over this holiday season is between $80.31 and $89.11.</em>

FALSE. The CI is related to the populations mean. We are 95% confident that the average spending of the population is between $80.31 and $89.11.

<em>This confidence interval is valid since the sampling distribution of sample mean would be approximately normal with sample size of 436.</em>

TRUE. This happens accordingly to the Central Limit Theorem.

<em>95% of random samples have a sample mean between $80.31 and $89.11.</em>

FALSE. The confidence interval refers to the population mean.

<em>We are 95% confident that the average spending of all American adults over this holiday season is between $80.31 and $89.11.</em>

TRUE. This is the conclusion that is looked for when constructing a confidence interval.

6 0
4 years ago
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