All categories

2 years ago

Write an equation for the following: (3,-2) and a slope of -2

Mathematics

1 answer:

White raven [17]2 years ago

4 0

Answer:

y=-2x+4

Step-by-step explanation:

y-y1=m(x-x1)

y-(-2)=-2(x-3)

y+2=-2x+6

y=-2x+6-2

y=-2x+4

You might be interested in

Two intersecting lines will form how many pairs of congruent angles?

HACTEHA [7]

Two intersecting lines will form 2 pairs of congruent vertical angles. Congruent angles have the same angle measure and vertical angles are opposite angles formed by two intersecting lines. Hope this helps.

7 0

2 years ago

Jill has been watching the squirrels that live in her neighborhood. The number of squirrels changes each week. n f(n). 1 8. 2 12

qaws [65]

Answer: D) $f(n)=8(1.5)^{n-1}$

Step-by-step explanation:

From the given table we can see that this is not representing a linear function as the rate of change is not constant.

So it can be exponential growth function $A(b)^{n-1}$ , where A is the initial amount , b is the multiplicative rate of growth and n is the time period in weeks.

Now here at n=1 , f(n)=8

Therefore, A=8

Now, for n=2

$f(2)=8(b)^{2-1}\\\Rightarrow12=8b\\\Rightarrow\ b=\frac{12}{8}\\\Rightarrow\ b=1.5$

By substitute the values of A and b in the above equation, we get the equation $f(n)=8(1.5)^{n-1}$

Therefore, the function best shows the relationship between n and f(n) is

$f(n)=8(1.5)^{n-1}$ , where n is the number of weeks.

7 0

2 years ago

Read 2 more answers

Consider the equation y = 3(x-5)(x +2)

lara31 [8.8K]

-x intercepts: 5, -2
-1/2(x-5)(x+2) is wider than the first equation because the coefficient is smaller

4 0

2 years ago

Helene wrote a report. It took her 4 hours to write 24 pages.

sammy [17]

Answer:

Step-by-step explanation:

24÷6= 6 Hope this helps.

4 0

3 years ago

Evaluate the following double integral: xy dA D where the region D is the triangular region whose vertices are (0, 0), (0, 3), (

natulia [17]

Answer:

I= 84

Step-by-step explanation:

for

$I=\int\limits^{}_{} \int\limits^{}_D {x*y} \, dA = \int\limits^{}_{} \int\limits^{}_D {x*y} \, dx*dy$

since D is the rectangle such that 0<x<3 , 0<y<3

$I=\int\limits^{}_{} \int\limits^{}_D {x*y} \, dA = \int\limits^{3}_{0} \int\limits^{3}_{0} {x*y} \, dx*dy = \int\limits^{3}_{0} {x} \, dx\int\limits^{3}_{0} {y} \, dy = x^{2} /2*y^{2} /2 = (3^{2} /2 - 0^{2} /2)* (3^{2} /2 - 0^{2} /2) = 3^{4} /4 = 81/4$

4 0

2 years ago