Answer:
1. x =0; x = -7
2. x = -3; x = 10
3. x = -5; x = -4
Step-by-step explanation:
(1). 6x² + 42x = 0
6x (x + 7) = 0
6x = 0. OR. x + 7 = 0
x = 0/6. x = 0 - 7
x = 0. x = -7
x = 0
x = -7
(2). x² - 7x - 30 = 0
The factors here are (3, -10)
x² - 10x + 3x - 30 = 0
x ( x - 10) + 3 ( x - 10) = 0
(x + 3) ( x - 10) = 0
x + 3 = 0 OR. x - 10 = 0
x = 0-3. x = 0 + 10
x = -3. x = 10
x = -3
x = 10
(3). x² + 9x + 20 = 0
The factors are ( 4, 5)
x² + 4x + 5x + 20 = 0
x ( x + 4) + 5 ( x + 4) = 0
(x + 5) (x + 4) = 0
x + 5 = 0 . OR. x + 4 = 0
x = 0-5. x = 0 - 4
x = -5. x = -4
x = -5
x = -4
4x+1+57=90
4x+58=90
4x=32
X=8
Answer:
the second one iy s very incorrect
Answer:
what?
Step-by-step explanation:
Answer: The answer is (b) [(p∧q)⇒r] ∧ [r⇒(p∧q)].
Step-by-step explanation: Given that The statements 'p', 'q' and 'r' are defined as follows.
p : it is cold,
q : it is humid,
r : it is snowing.
The statement 'it is cold and humid if and only if it is snowing' can be written as
(p∧q) ⇔ r.
We know that r ⇔ s can be written as (r⇒s)∧(s⇒r).
So, (p∧q) ⇔ r can be written as [(p∧q)⇒r] ∧ [r⇒(p∧q)].
Thus, the answer is (b) [(p∧q)⇒r] ∧ [r⇒(p∧q)].
