X²+15x+36<0
at first solve quadratic equation
D=b²-4ac= 225-4*1*36= 81
x=(-b+/-√D)/2a
x=(-15+/-√81)/2= (-15+/-9)/2
x1=(-15-9)/2=-12
x2=(-15+9)/2=-3
we can write x²+15x+36<0 as (x+12)(x+3)<0
(x+12)(x+3)<0 can be 2 cases, because for product to be negative one factor should be negative , and second factor should be positive
1 case) x+12<0, and x+3>0,
x<-12, and x>-3
(-∞, -12) and(-3,∞) gives empty set
or second case) x+12>0 and x+3<0
x>-12 and x<-3
(-12,∞) and (-∞,-3) they are crossing , so (-12, -3) is a solution of this inequality
Answer:
15 inches
Step-by-step explanation:
Suppose length of original square is L inches.
Now, to form a new square the length increases by 2.5 inches
So, new length=L+2.5 inches
Given that, perimeter of new square =70 inches.
Formula:-
Perimeter=4*length of square
Therefore 70=4*(L+2.5)
70 =4 L+10
4 L=60
L=15 inches
Answer:
a) Total 16 possibilities
MMMM
FFFF
MMMF
MMFM
MFMM
FMMM
FFFM
FFMF
FMFF
MFFF
MMFF
MFMF
MFFM
FFMM
FMMF
FMFM
b) P(MMMM) = 1/16
Answer: C
Step-by-step explanation:
