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Ray Of Light [21]
3 years ago
6

2 Solve the equation 3x +125 = 49

Mathematics
1 answer:
Alex787 [66]3 years ago
8 0

Qustion:

3x +125 = 49

Answer:

x = - 25 1/3

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aivan3 [116]
Standard form of an equation is ax + by = c, which in this case is 5x + 3y = 14, or B.
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If anyone could please help me with both these questions if not then at least do one I would appreciate it a lot! Please and Tha
Andreas93 [3]
Unit is 72 because it is the length
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At Taylor Street School, 40% of the students bought lunch in the cafeteria today. Of the students who bought lunch in the cafete
leva [86]

Answer:

  Probability that she or he bought lunch in the cafeteria and chose pizza as an entree = 12/100 =0.12 = 12%

Explanation:

  Let number of students be 100.

  At Taylor Street School, 40% of the students bought lunch in the cafeteria today

 Number of students bought lunch = 100 x 40/100 = 40

 Of the students who bought lunch in the cafeteria today, 30% chose pizza as their entree

 Number of students bought pizza = 40 x 30/100 = 12.

 Probability of an outcome = Number of favorable outcome/ Total number of outcome

 Probability that she or he bought lunch in the cafeteria and chose pizza as an entree = Number of students bought pizza/Total number of students

        = 12/100 =0.12 = 12%

  Probability that she or he bought lunch in the cafeteria and chose pizza as an entree = 12/100 =0.12 = 12%

4 0
4 years ago
Ken made &14,500 in five months at his new job how much can he expect to make in two years if his pay remains constant
solniwko [45]

Answer:

$69,600

Step-by-step explanation:

$14,500 in 5 months,

14,500/5=2,900

so he makes $2,900 each month,

1 year=12 months

2 years=24 months

-------------------------------------------------

2900*24=69600

so he expects to make $69,600 in two years.

4 0
3 years ago
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How do you do this problem? I need to know how you found the answer.
Alexxandr [17]

to get the equation of a line, we simply need two points, say for the Red one ... notice in the graph the lines passes through (0,2) and (-1,6), so let's use those


\bf (\stackrel{x_1}{0}~,~\stackrel{y_1}{2})\qquad (\stackrel{x_2}{-1}~,~\stackrel{y_2}{6}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{6-2}{-1-0}\implies \cfrac{4}{-1}\implies -4 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-2=-4(x-0) \\\\\\ y-2=-4x\implies \blacktriangleright y=-4x+2 \blacktriangleleft


now, for the Blue one, say let's use hmmm it passes through (0,2) and (1.6)


\bf (\stackrel{x_1}{0}~,~\stackrel{y_1}{2})\qquad (\stackrel{x_2}{1}~,~\stackrel{y_2}{6}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{6-2}{1-0}\implies \cfrac{4}{1}\implies 4 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-2=4(x-0) \\\\\\ y-2=4x\implies \blacktriangleright y=4x+2 \blacktriangleleft

3 0
3 years ago
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