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Ray Of Light [21]
3 years ago
6

2 Solve the equation 3x +125 = 49

Mathematics
1 answer:
Alex787 [66]3 years ago
8 0

Qustion:

3x +125 = 49

Answer:

x = - 25 1/3

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The 7th grade class is putting on a variety show to raise money. It cost $700 to rent the banquet hall that they are going to us
scoundrel [369]

Answer:

At least 20 people

Step-by-step explanation:

Ⓗⓘ ⓣⓗⓔⓡⓔ

Well, the equation is 700+15x=1000

700+15x=1000

15x=300

x=20

(っ◔◡◔)っ ♥ Hope this helped! Have a great day! :) ♥

Please, please give brainliest, it would be greatly appreciated, I only a few more before I advance, thanks!

5 0
4 years ago
Gina had a scrambled egg and a cup of low-fat milk for breakfast. She had an oat bran muffin for a morning snack. Grams of Prote
Softa [21]

Answer:

She takes 11 grams more protein for breakfast than for a snack.

Step-by-step explanation:

Consider the provided information.

Gina had a scrambled egg and a cup of low-fat milk for breakfast.

She had an oat bran muffin for a morning snack.

First round up the numbers as shown below:

Food Protein (in grams) 1 scrambled egg 6.71 ≈ 7

1 cup shredded wheat cereal 5.51 ≈ 6

1 oat bran muffin 3.98 ≈ 4

1 cup low-fat milk 8.22 ≈ 8

Protein in Breakfast = a scrambled egg + a cup of low-fat milk

Protein in Breakfast = 7+8 = 15

Morning snack she had an oat bran muffin.

Protein in Morning snack = 4

Now we need to find how many more grams of protein did Gina have for breakfast than for a snack?

So subtract them as shown below:

15-4 = 11

Hence, she takes 11 grams more protein for breakfast than for a snack.

5 0
3 years ago
Please help<br> Show workings
Roman55 [17]

Answer:

this ange is congruent to the one above so you would just subtract 180 from 116

180-116

= 64

5 0
3 years ago
At 2:00 PM a car's speedometer reads 30 mi/h. At 2:15 PM it reads 50 mi/h. Show that at some time between 2:00 and 2:15 the acce
g100num [7]

Here is the correct format for the question

At 2:00 PM a car's speedometer reads 30 mi/h. At 2:15 PM it reads 50 mi/h. Show that at some time between 2:00 and 2:15 the acceleration is exactly 80 mi/h².Let v(f) be the velocity of the car t hours after 2:00 PM.Then \dfrac{v(1/4)-v(0)}{1/4 -0} = \Box. By the Mean Value Theorem, there is a number c such that 0 < c < \Box  with v'(c) = \Box. Since v'(t)  is the acceleration at time t, the acceleration c hours after 2:00 PM is exactly 80 mi/h^2.

Answer:

Step-by-step explanation:

From the information given :

At  2:00 PM ;

a car's speedometer v(0) = 30 mi/h

At 2:15 PM;

a car's speedometer v(1/4) = 50 mi/h

Given that:

v(f) should be the velocity of the car t hours after 2:00 PM

Then \dfrac{v(1/4)-v(0)}{1/4 -0} = \Box will be:

= \dfrac{50-30}{1/4 -0}

= \dfrac{20}{1/4 }

= 20 × 4/1

= 80 mi/h²

By the Mean value theorem; there is a number c such that :

\mathbf{0 < c< \dfrac{1}{4}}     with \mathbf{v'(c) = \dfrac{v(1/4)-v(0)}{1/4 -0}} \mathbf{ = 80 \ mi/h^2}

6 0
3 years ago
If f(x)=7x and g(x)=6x-3,find (f*g)(x)
Dovator [93]
(f\cdot g)(x)=f(x)\cdot g(x)\\\\&#10;(f\cdot g)(x)=7x(6x-3)=42x^2-21x&#10;
7 0
4 years ago
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