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3 years ago

SOMEONE please just explain this to me I need to pass

Mathematics

1 answer:

Anika [276]3 years ago

3 0

Ok so slope is y2-y1/x2-x1. the question is asking you to find the value of x1 that will make the slope 7. plug in your coordinates to get (7-(-7))/(4-s)=7, then you simplify to get 14/(4-s)=7, multiply both sides by (4-s) to get 14=7(4-s), divide both sides by 7 to get 2=4-s, and then solve to get that s=2. hope this helps!

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Name each polynomial by degree amd number of terms 6p^4 + 10p^2

Volgvan

Two term quartic, or degree 4 polynomial

5 0

3 years ago

Write the equation of the line that passes through the two points: (-4, 11) and (2,-4)

snow_tiger [21]

Answer:

y= - $\frac{5}{2}$ x+1

Step-by-step explanation:

Utilize the formula of $\frac{y2-y1}{x2-x1}$ to find the distance between two points, or in this case, the equation of the line that passes through two points.

Applying the given points to identify the slope

1. Plug the coordinates into the y and x values. $\frac{-4-11}{2+4}$ =- $\frac{15}{6}$ .

1.5. Simplify; divide both the numerator and the denominator by 3. - $\frac{5}{2}$ .

Applying slope and a point to find the y-intercept of the equation of a line

1. Utilize the formula of y=mx. Though this sounds strange, morph the sign of equality into subtraction.

1.5. Result: y-mx

2. Do this for both points.

First point: (-4,11)

y-mx

11 + $\frac{5}{2}$ (-4)

11 + -10 (11-10)

Plug the result and the slope into y=mx+b to find the slope of the line.

Result: y=- $\frac{5}{2}$ x+1.

Check your answer to confirm that the value of y is true for both points

1. Do the same thing you did with the first point, but use the second point this time.

y-mx

-4 + $\frac{5}{2}$ (2)

-4 + 5

Plug the result and the slope into y=mx+b to find the slope of the line.

Result: y=- $\frac{5}{2}$ x+1. Identical to point one's result.

In conclusion, both of the results are the same. Therefore, the equation of the line must be y=- $\frac{5}{2}$ x+1.

3 0

4 years ago

43 cents written as a percent of $1 can be written as..

xz_007 [3.2K]

43 percent

1$ is equal to 100 cents, so 43 cents out of 100 cents, or 43/100 equals 43 percent

3 0

4 years ago

Read 2 more answers

I need help please ASAP thank you

kirza4 [7]

Answer:

The products of AB and BA is given by

AB= $\left[\begin{array}{cc}21&-6\\ 9&3\end{array}\right]$

BA= $\left[\begin{array}{cc}9&-1\\-18&15\end{array}\right]$

Step-by-step explanation:

Given the matrices A= $\left[\begin{array}{cc}6&-5\\-3&-4\end{array}\right]$ and

B= $\left[\begin{array}{cc}1&-1\\-3&0\end{array}\right]$

To find the product AB and BA

AB= $\left[\begin{array}{cc}6&-5\\-3&-4\end{array}\right] \left[\begin{array}{cc}1 & -1\\-3 &0\end{array}\right]$

$=\left[\begin{array}{cc}6+15& -6+0\\-3+12&3-0\end{array}\right]$

Therefore the product of AB is

AB= $\left[\begin{array}{cc}21&-6\\ 9&3\end{array}\right]$

BA= $\left[\begin{array}{cc}1&-1\\-3&0\end{array}\right]$ $\left[\begin{array}{cc}6&-5\\-3&-4\end{array}\right]$

$=\left[\begin{array}{cc}6+3& -5+4\\-18+0&15+0\end{array}\right]$

Therefore the product of BA is

BA= $\left[\begin{array}{cc}9&-1\\-18&15\end{array}\right]$

The products of AB and BA is given by

AB= $\left[\begin{array}{cc}21&-6\\ 9&3\end{array}\right]$

BA= $\left[\begin{array}{cc}9&-1\\-18&15\end{array}\right]$

6 0

3 years ago

One packet of biscuits requires 2 15/16 and 1 7/8 cups of sugar. Estimated total quantity of both ingredients used in 10 such pa

frez [133]

Answer:

Hey Mate! Here's your answer.

Step-by-step explanation:

One packet of biscuits requires 2½ cups of flour = \frac{5}{2}25

One packet of biscuits requires 1 \times \frac{2}{3}1×32

One packet of biscuits requires 1 \times \frac{2}{3}1×32cups of sugar. = \frac{5}{3}35

Total ingradiants for one packet of biscuits =

Total ingradiants for one packet of biscuits =( \frac{5}{2} + \frac{5}{3} ) = \frac{15 + 10}{6} = \frac{25}{6}(25+35)=615+10=625

Then, total quantity of both ingredients used in 10 such packets of biscuits =

Then, total quantity of both ingredients used in 10 such packets of biscuits =10 \times ( \frac{25}{6} ) = 5 \times ( \frac{25}{3} ) = \frac{125}{3} = 41 \times \frac{2}{3}10×(625)=5×(325)=3125=41×32

Hope it helped you!

7 0

3 years ago