Answer: x=13
Step-by-step explanation:
To take out terms outside the radical we need to divide the power of the term by the index of the radical; the quotient will be the power of the term outside the radical, and the remainder will be the power of the term inside the radical.
First, lets factor 8:
Now we can divide the power of the term, 3, by the index of the radical 2:
![\frac{3}{2}](https://tex.z-dn.net/?f=%20%5Cfrac%7B3%7D%7B2%7D%20)
= 1 with a remainder of 1
Next, lets do the same for our second term
![x^{7}](https://tex.z-dn.net/?f=%20x%5E%7B7%7D%20)
:
![\frac{7}{2}](https://tex.z-dn.net/?f=%20%5Cfrac%7B7%7D%7B2%7D%20)
= 3 with a remainder of 1
Again, lets do the same for our third term
![y^{8}](https://tex.z-dn.net/?f=y%5E%7B8%7D%20)
:
![\frac{8}{2} =4](https://tex.z-dn.net/?f=%20%5Cfrac%7B8%7D%7B2%7D%20%3D4)
with no remainder, so this term will come out completely.
Finally, lets take our terms out of the radical:
![\sqrt{8x^{7} y^{8} }= \sqrt{ 2^{3} x^{7} y^{8} } =2 x^{3} y^{4} \sqrt{2x}](https://tex.z-dn.net/?f=%20%20%5Csqrt%7B8x%5E%7B7%7D%20y%5E%7B8%7D%20%20%7D%3D%20%5Csqrt%7B%202%5E%7B3%7D%20x%5E%7B7%7D%20y%5E%7B8%7D%20%20%20%7D%20%20%3D2%20x%5E%7B3%7D%20%20y%5E%7B4%7D%20%20%5Csqrt%7B2x%7D%20)
We can conclude that the correct answer is the third one.
The mean absolute deviation of a number set is the average distance between each value and the mean.<span> This is obtained by finding the mean of the set, determining the absolute value difference between each number, and the mean and calculating the average of these differences.
The mean of the set is ( 26 + 43 + 48 + 29 + 16 + 30 ) / 6 = 32 ;
</span> the absolute value difference between each number:
/ 26 - 32 / = 6 ; / 43 - 32 / = 11 ; / 48 - 32 / = 16 ; / 29 - 32 / = 3 ; / 16 - 32 / = 16 ;
/ 30 - 32 / = 2 ;
the mean absolute deviation of 26 43 48 29 16 30 is ( 6 + 11 + 16 + 3 + 16 + 2 ) / 6 = 9 ;
Step-by-step explanation:
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