Hi there!

Let there be two angles, ∠A and ∠B, that are supplementary to each other. Therefore:
∠A + ∠B = 180°
We can assign ∠B to be the greater angle. Assume ∠A has a measure of x°.
∠A = x°
∠B = x° + 30°
The sum is equal to 180°, so:
x° + (x° + 30°) = 180°
Solve for x°.
2x° + 30° = 180°
2x° = 150°
x° = 75°
Thus, ∠A = 75°.
Since ∠B is 30°, greater:
∠B = 75° + 30° = 105°.
Answer:
Sin theta = 12/13
Step-by-step explanation:
From the question;
Cot theta = 5/12
Kindly recall;
Cot theta = 1/ tan theta
Hence, tan theta = 12/5
Mathematically
tan theta= opposite/adjacent
to get hypotenuse, we will use Pythagoras’ theorem which states that the square of the hypotenuse equals sum of the squares of the two other sides
let hypotenuse be h
h^2 = 12^2 + 5^2
h^2 = 144 + 25
h^2 = 169
h = √169
h = 13
But sine theta = opposite/ hypotenuse = 12/13
the answer should be if i did my math right is 0.25
Answer:

Step-by-step explanation:
The Side-Angle-Side method cana only be used when information given shows that an included angle which is between two sides of a ∆, as well as the two sides of the ∆ are congruent to the included side and two sides of the other ∆.
Thus, since John already knows that
and
, therefore, an additional information showing that the angle between
and
in ∆ABC is congruent to the angle between
and
in ∆DEF.
For John to prove that ∆ABC is congruent to ∆DEF using the Side-Angle-Side method, the additional information needed would be
.
See attachment for the diagram that has been drawn with the necessary information needed for John to prove that ∆ABC is congruent to ∆DEF.
Answer:
Step-by-step explanation:
2x + 5 = -x - 1
3x + 5 = -1
3x = -6
x = -2
y = 2 - 1
y = 1
(-2, 1)