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Tasya [4]
3 years ago
11

The terminal point of Dis ( 1/2,3/2). What is cos 0?

Mathematics
1 answer:
nydimaria [60]3 years ago
5 0

Answer:

<em>(c). </em>\frac{1}{2}<em> </em>

Step-by-step explanation:

The <u><em>cosine</em></u> is the <em>"x" coordinate</em> of the terminal point on the unit circle.

Thus the answer is <em>(c). </em>\frac{1}{2}

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The answer is 4.35, rounded two decimals to hundredths place.

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2 years ago
Rachel is a lunchroom supervisor at West School. The children eat lunch at 15 long tables. When all tables are used, 240 childre
Diano4ka-milaya [45]
240÷15=16 seats at each table

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Create and solve an appropriate equation:  Maria's earnings = Liam's earnings

                                                                       0.20x                 = $625+0.10x.

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0.10x = $625; thus, x = $6250.  At this level of food sales, these two people earn the same amount.
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Question 5
Vikentia [17]

The amount of sales (S) of statin in billions of dollars by 2017 is 34.5 billions

<h3>Linear equations</h3>

Linear equation are equation that has a leading degree of 1. Given the equation that represents Statins used to keep cholesterol in check and are a top-selling drug in the U.S.

S-1.5x = 6

where

S is the amount of sales

x is the number of years after 1998

By 2017, the total number of  years is 19 years

Substitute

S = 1.5x + 6

S = 1.5(19) + 6

S = 28.5 + 6

S = 34.5

The amount of sales (S) of statin in billions of dollars by 2017 is 34.5 billions

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6 0
1 year ago
HELP ASAP
Andrei [34K]

Answer:

radius = \sqrt{13} or radius = 3.61

Step-by-step explanation:

Given

Points:

A(-3,2) and B(-2,3)

Required

Determine the radius of the circle

First, we have to determine the center of the circle;

Since the circle has its center on the x axis; the coordinates of the center is;

Center = (x,0)

Next is to determine the value of x through the formula of radius;

radius = \sqrt{(x_1 - x)^2 + (y_1 - y)^2} = \sqrt{(x_2 - x)^2 + (y_2 - y)^2}

Considering the given points

A(x_1,y_1) = A(-3,2)

B(x_2,y_2) = B(-2,3)

Center(x,y) =Center (x,0)

Substitute values for x,y,x_1,y_1,x_2,y_2 in the above formula

We have:

\sqrt{(-3 - x)^2 + (2 - 0)^2} = \sqrt{(-2 - x)^2 + (3 - 0)^2}

Evaluate the brackets

\sqrt{(-(3 + x))^2 + 2^2} = \sqrt{(-(2 + x))^2 + 3 ^2}

\sqrt{(-(3 + x))^2 + 4} = \sqrt{(-(2 + x))^2 + 9}

Eva;uate all squares

\sqrt{(-(3 + x))(-(3 + x)) + 4} = \sqrt{(-(2 + x))(-(2 + x)) + 9}

\sqrt{(3 + x)(3 + x) + 4} = \sqrt{(2 + x)(2 + x) + 9}

Take square of both sides

(3 + x)(3 + x) + 4 = (2 + x)(2 + x) + 9

Evaluate the brackets

3(3 + x) +x(3 + x) + 4 = 2(2 + x) +x(2 + x) + 9

9 + 3x +3x + x^2 + 4 = 4 + 2x +2x + x^2 + 9

9 + 6x + x^2 + 4 = 4 + 4x + x^2 + 9

Collect Like Terms

6x -4x + x^2 -x^2 = 4 -4 + 9 - 9

2x = 0

Divide both sides by 2

x = 0

This implies the the center of the circle is

Center = (x,0)

Substitute 0 for x

Center = (0,0)

Substitute 0 for x and y in any of the radius formula

radius = \sqrt{(x_1 - 0)^2 + (y_1 - 0)^2}

radius = \sqrt{(x_1)^2 + (y_1)^2}

Considering that we used x1 and y1;

In this case we have that; A(x_1,y_1) = A(-3,2)

Substitute -3 for x1 and 2 for y1

radius = \sqrt{(-3)^2 + (2)^2}

radius = \sqrt{13}

radius = 3.61 ---<em>Approximated</em>

7 0
4 years ago
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