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Tasya [4]
3 years ago
11

The terminal point of Dis ( 1/2,3/2). What is cos 0?

Mathematics
1 answer:
nydimaria [60]3 years ago
5 0

Answer:

<em>(c). </em>\frac{1}{2}<em> </em>

Step-by-step explanation:

The <u><em>cosine</em></u> is the <em>"x" coordinate</em> of the terminal point on the unit circle.

Thus the answer is <em>(c). </em>\frac{1}{2}

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An angle measures 30° more than the measure of its supplementary angle. What is the measure of each angle?
yarga [219]

Hi there!
\boxed{\angle A = 75^o, \angle B = 105^o}

Let there be two angles, ∠A and ∠B, that are supplementary to each other. Therefore:

∠A + ∠B = 180°

We can assign ∠B to be the greater angle. Assume ∠A has a measure of x°.

∠A = x°

∠B = x° + 30°

The sum is equal to 180°, so:

x° + (x° + 30°) = 180°

Solve for x°.

2x° + 30° = 180°

2x° = 150°

x° = 75°

Thus, ∠A = 75°.

Since ∠B is 30°, greater:
∠B = 75° + 30° = 105°.

4 0
1 year ago
Suppose Cotangent (theta) = StartFraction 5 Over 12 EndFraction, where Pi less-than theta less-than StartFraction 3 pi Over 2 En
Agata [3.3K]

Answer:

Sin theta = 12/13

Step-by-step explanation:

From the question;

Cot theta = 5/12

Kindly recall;

Cot theta = 1/ tan theta

Hence, tan theta = 12/5

Mathematically

tan theta= opposite/adjacent

to get hypotenuse, we will use Pythagoras’ theorem which states that the square of the hypotenuse equals sum of the squares of the two other sides

let hypotenuse be h

h^2 = 12^2 + 5^2

h^2 = 144 + 25

h^2 = 169

h = √169

h = 13

But sine theta = opposite/ hypotenuse = 12/13

5 0
2 years ago
Can someone help . 8th grade math.
SVETLANKA909090 [29]

the answer should be if i did my math right is 0.25


8 0
3 years ago
Pls Help! John wants to prove ABC = to DEF. He Knoes AB = DE and AC = DF. With Screenshot
matrenka [14]

Answer:

\angle A \cong \angle D

Step-by-step explanation:

The Side-Angle-Side method cana only be used when information given shows that an included angle which is between two sides of a ∆, as well as the two sides of the ∆ are congruent to the included side and two sides of the other ∆.

Thus, since John already knows that \overline{AB} \cong \overline{DE} and \overline{AC} \cong \overline{DF}, therefore, an additional information showing that the angle between \overline{AB} and \overline{DE} in ∆ABC is congruent to the angle between \overline{AC} and \overline{DF} in ∆DEF.

For John to prove that ∆ABC is congruent to ∆DEF using the Side-Angle-Side method, the additional information needed would be \angle A \cong \angle D.

See attachment for the diagram that has been drawn with the necessary information needed for John to prove that ∆ABC is congruent to ∆DEF.

7 0
2 years ago
Solve the following system by graphing.<br> Y =<br> 2 + 5<br> y = -x-1
Klio2033 [76]

Answer:

Step-by-step explanation:

2x + 5 = -x  - 1

3x + 5 = -1

3x = -6

x = -2

y = 2 - 1

y = 1

(-2, 1)

4 0
3 years ago
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