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Lisa [10]
3 years ago
9

Help me of i die so pls help me

Mathematics
1 answer:
nekit [7.7K]3 years ago
7 0

Answer:

10

100

1000

Step-by-step explanation:

I had a quiz on that the other day got 100%

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A huge Ping-Pong tournament is held in Beijing with 65,536 participants at the start of the tournament. Each round of
lisabon 2012 [21]

Answer:

After 16 rounds the champion of Ping-Pong player can be determined.

Step-by-step explanation:

This is an example of geometric progression,

First term = 65,536

\texttt{Common ratio = }\frac{1}{2}

Now we need to find which term is 1 in this GP.

N th term of GP is given by

             t_n=ar^{n-1}

Substituting

               1=65536\times \left ( \frac{1}{2}\right )^{n-1}\\\\\frac{1}{65536}=\left ( \frac{1}{2}\right )^{n-1}\\\\2^{n-1}=65536\\\\2^{n-1}=2^{16}\\\\n=17

Seventeenth term of this GP is 1.

That is after 16 rounds the champion of Ping-Pong player can be determined.

3 0
3 years ago
Help plz i have a f in this class
Mnenie [13.5K]

Answer:

For number 3 the answer is -4

4 0
2 years ago
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Helppp 1,2,3,4,5 please as fast as you can
Vladimir [108]
Weather I think I'm not sure
6 0
3 years ago
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Question 5: How long will it take for 2 g of a sample of iodine-131, which has a half-life of about 8 days, to decay to 0.04 g?
Aleonysh [2.5K]

This problem can be represented through the following equation

A = A₀(1/2)^t/h

where

A----------->  is the amount of substance left after time t

A₀ ----------> is the original amount---------> 2 g

h------------->  is the half-life-----------> 8 days

for A=0.04 g

t=?

0.04 = 2(1/2)^t/8

0.02 = (1/2)^t/8

Take ln on both sides:

ln(0.02) = ln [(1/2)^t/8]

ln(0.02) = (t/8)(ln 1/2)

t = 8*ln(0.02)/ln(1/2)

t = 45.15 days

the answer is 45.15 days

4 0
3 years ago
A room has three lightbulbs. Each one has a 30% probability of burning out within the month. Write the probability as a percenta
lesantik [10]

Answer:

97.3%

Step-by-step explanation:

Let the three bulbs be A, B and C respectively.

Let P(A) denote the probability that the first bulb will burn out

Let P(B) denote the probability that the second bulb will burn out

Let P(C) denote the probability that the third bulb will burn out

Now, we are told that Each one has a 30% probability of burning out within the month.

Thus;

P(A) = P(B) = P(C) = 30% = 0.3

Now, probability that at the end of the month at least one of the bulbs will be lit will be given as;

P(at least one bulb will be lit) = 1 - (P(A) × P(B) × P(C))

P(at least one bulb will be lit) = 1 - (0.3 × 0.3 × 0.3) = 0.973 = 97.3%

3 0
3 years ago
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