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Anna [14]
3 years ago
5

What's the area of a square picture with 16 inch sides

Mathematics
2 answers:
Aneli [31]3 years ago
5 0
The area of a square can be found by squaring the side length. So, the area of the picture can be found by multiplying 16 by 16. 16 x 16 is 256.
iVinArrow [24]3 years ago
5 0
256 Square inches is the answer
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The first four terms of an arithmetic sequence are -11,-5,1,7. what is the equation for an
mr_godi [17]

Answer:

y = 6x - 11

Step-by-step explanation:

An arithmetic sequence is a linear function. This means it steadily increases or decreases through addition/subtraction by a constant amount. Here the sequence grows by adding 6 each time.

-11 + 6 = -5

-5 + 6 = 1

1 + 6 = 7

etc....

Since this is linear, its equation has the form y = mx + b where m is the slope and b is the y-intercept. The slope is m = 6 and b = -11.

y = 6x - 11

7 0
3 years ago
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mash [69]
The table says that the x value represents the number the years since 1985. To find the number of bald eagle pairs in 1998, we need to calculate x:

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6 0
3 years ago
Is the equation conditional, an identity, or a contradiction? y - 11 + 3y = 6y + 4
ipn [44]

Answer:

The equation is a conditional.

y = 7.5

Step-by-step explanation:

y - 11 + 3y = 6y + 4

4y - 11 = 6y + 4

4y - 4y - 11 = 6y - 4y + 4

- 11 = 2y + 4

- 11 - 4 = 2y + 4 - 4

2y = - 15

2y ÷ 2 = - 15 ÷ 2

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8 0
3 years ago
There are 5 pens in a container on your desk. Among them, 3 will write well but 2 have defective ink cartridges. You will select
Norma-Jean [14]

Answer:

Kindly check explanation

Step-by-step explanation:

Total Number of pens = 5

Number of defective pens = 2

Number of non-defective pens = 3

A.) number of defective pens selected :

X : {0, 1, 2}

It is possible that no defective pen will be selected ; 1 defective will be chosen or both pens are defective.

2.)

Defective as Success (since selecting a defective pen is the point of interest.

3.)

Since selection is done without replacement

Probability of success per selection is different for each selection ;

Number of defective = 2

Number of observations = 5

P(success on first selection) = 2/5

P(success on second selection) = 1/4

Hence, X is not well approximated by a binomial random variable.

4.) if selection is done with replacement ; then then the probability of success per selection will be the Same for each selection made. Hence, X will be well approximated by a binomial Random variable.

5.) If sampling is done without replacement, then the the hypergeometric function will be a more effective approximation.

7 0
3 years ago
Determine 2 additional fractions that would reduce to one fourth?
Len [333]

Answer:

2/8, 4,16

Step-by-step explanation:

6 0
3 years ago
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