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wariber [46]
3 years ago
11

Given a circle with measures of (C, d, and r) and a circle with measures of (C', d', and r), what is r if c/c’ = 5 and d' = 20?

Mathematics
1 answer:
PtichkaEL [24]3 years ago
7 0
The answer to your problem is. C)50
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Factor the quadratic by checking factor pairs.<br> -15x2 – 21x + 18<br> -15x2 – 218 + 19 = -3
d1i1m1o1n [39]

Answer:

-3(x + 2)(5x - 3)

Step-by-step explanation:

-15x² – 21x + 18

-3(5x² + 7x - 6)

-3[5x² + 10x - 3x - 6]

-3[5x(x + 2) - 3(x + 2)]

-3(x + 2)(5x - 3)

3 0
4 years ago
Step by step please help answer.
sweet-ann [11.9K]

Answer:

(2) 2,640 ft

Step-by-step explanation:

I'm going to assume that in this question, you are walking 1 full circle around the reservoir. That would mean you need to calculate the circumference of the circular reservoir.

The circumference formula is:

C = ⫪d

C stands for Circumference

d stands for diameter

I will use 22/7 instead of pi, so the formula looks more like this:

C = (22/7)(d)

The diameter is 840 feet, so we will substitute the variable d with 840:

C = (22/7)(840)

You can plug this part into the calculator, but by hand, it'll look something like this:

(22/7)*840 = (22*840)/7

18,480/7 = 2.640

Hope it helps (●'◡'●)

5 0
3 years ago
-5d + 11 = 8 - 3d<br> -5d + 11 + 3d = 8 - 3d + 3d
rjkz [21]

Answer:

do you have any options to choose from

5 0
3 years ago
Mr. Herman's class is selling candy for a school fundraiser. The class has a goal of raising $500 by selling C
katovenus [111]

Answer:

2.75 x (c) = 500

Step-by-step explanation:

i think this is it

8 0
3 years ago
Give the equation of the line perpendicular to y +7= -2(x - 6) through the<br> point (6,-3)
lilavasa [31]

<u>Note: this answer assumes the equation of the line can be put in slope-intercept form. </u>

Answer:

y + 3 = \frac{1}{2}(x-6)

Step-by-step explanation:

1) First, find the slope of y + 7 = -2 (x - 6). We can see that it's already in point-slope form, or y-y_1 = m (x-x_1) format. Remember that the number in place of the m is the slope. Therefore, -2 is the slope of that equation.

What we need is the slope that is perpendicular to that, though. So, find the opposite reciprocal of -2. To do this, change its sign, convert it into a fraction (-\frac{2}{1}), and flip its numerators and denominators. Therefore, the perpendicular slope would be \frac{1}{2}.

2) Now that we have a slope and a point the line passes through, we can write an equation using the point-slope formula, y-y_1 = m (x-x_1). In order to write an equation, the x_1, y_1, and m have to be substitute for with real values.

The m represents the slope. We already calculated that in the last step, so put \frac{1}{2} in place of the m. The x_1 and y_1 represent the x and y values of a point the line passes through. We know that the line has to pass through (6, -3), so substitute 6 for x_1 and -3 for y_1:

y - (-3) = \frac{1}{2}(x -(6))\\y + 3 = \frac{1}{2}(x - 6)

Therefore, (again, assuming that the line can be put in point-slope form) the answer is y + 3 = \frac{1}{2}(x-6).

5 0
3 years ago
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