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Shalnov [3]
3 years ago
12

5 Raymond was riding a zip-cable from the top of a viewing post. The cable is 75 yards long. The viewing post is 60 yards high a

nd forms a right angle with the ground, as shown in the picture below. Given this information, how far is the bottom of the cable from the base of the viewing post?
Mathematics
2 answers:
Alenkasestr [34]3 years ago
7 0
It is 45 yd from the base of the pole.

The pieces of the right triangle we are given are one of the legs (the height of the pole, 60 yd) and the hypotenuse (the length of the cable, 75 yd).  Using the Pythagorean theorem, we have:

60²+b²=75²
3600+b²=5625

Subtract 3600 from both sides:
3600+b²-3600=5625-3600
b²=2025

Take the square root of both sides:
√(b²) = √2025
b = 45
Delicious77 [7]3 years ago
6 0

Answer:

It is 45

Step-by-step explanation:

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Read 2 more answers
An insurance company divides its policyholders into low-risk and high-risk classes. 60% were in the low-risk class and 40% in th
AleksAgata [21]

Answer:

a). 0.294

b) 0.11

Step-by-step explanation:

From the given information:

the probability of the low risk = 0.60

the probability of the high risk = 0.40

let C_o represent no claim

let C_1 represent 1 claim

let C_2 represent 2 claim :

For low risk;

so, C_o  = (0.80 * 0.60 = 0.48),  C_1 =  (0.15* 0.60=0.09),   C_2 = (0.05 *  0.60=0.03)

For high risk:

C_o  = (0.50 *  0.40 = 0.2),  C_1 =  (0.30 *  0.40 = 0.12) ,   C_2 = ( 0.20 *  0.40 = 0.08)

Therefore:

a),  the probability that a randomly selected policyholder is high-risk and filed no claims can be computed as:

P(H|C_o) = \dfrac{P(H \cap C_o)}{P(C_o)}

P(H|C_o) = \dfrac{(0.2)}{(0.48+0.2)}

P(H|C_o) = \dfrac{(0.2)}{(0.68)}

P(H|C_o) = 0.294

b) What is the probability that a randomly selected policyholder filed two claims?

the probability that a randomly selected policyholder be filled with two claims = 0.03 + 0.08

= 0.11

7 0
3 years ago
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