All categories

3 years ago

Someone please tell me the answers to this please I beg you

Mathematics

1 answer:

Wittaler [7]3 years ago

7 0

1) 216
2) 203
3) 315
4) 256
5) 576
6) 440

You might be interested in

What is the volume of a rectangular prism that has a length, width, and height of 1/2 m, 1/4 m, and 2/3 m, respectively?

Talja [164]

V = L * W * H
V = (1/2)(1/4)(2/3)
V = (1 * 1 * 2) / (2 * 4 * 3)
V = 2/24 reduces to 1/12 m <===

8 0

3 years ago

Which best describes the range of the function f(x) = 2(3)*?

Alex17521 [72]

Answer:

y > 0 best describes the range of the function f(x) = 2(3)x.

A function whose value is a constant raised to the power of the argument, especially the function where the constant is e.

If b is any number such that and then an exponential function is a function in the form, where b is called the base and x can be any real number.

Please vote brainiest!

8 0

3 years ago

Try again A light bulb consumes 5040 watt-hours in 3 days and 12 hours. How many watt-hours does it consume per day

White raven [17]

Answer:

1680 watt-hours

Step-by-step explanation:

consume per day

#carry on learning

5 0

2 years ago

What is x if f(x)=2^x is graphed

Amanda [17]

THIS CANNOT BE ANSWERED .......................................................................

5 0

3 years ago

Identify the radius and center.<br><br> x^2 + y^2 - 2x + 4y - 11 = 0

miss Akunina [59]

<h2>Hello!</h2>

The answer is:

Center: (1,-2)

Radius: 4 units.

To solve the problem, using the given formula of a circle, we need to find its standard equation form which is equal to:

$(x-h)^{2}+(y-k)^{2}=r^{2}$

Where,

"h" and "k"are the coordinates of the center of the circle and "r" is its radius.

So, we need to complete the square for both variable "x" and "y".

The given equation is:

$x^2+y^2-2x+4y-11=0$

So, solving we have:

$x^2+y^2-2x+4y=11$

$(x^2-2x+(\frac{2}{2})^{2} )+(y^2+4y+(\frac{4}{2})^{2})=11+(\frac{2}{2})^{2} +(\frac{4}{2})^{2}\\\\(x^2-2x+1)+(y^2+4y+4)=11+1+4\\\\(x^2-1)+(y^2+2)=16$

$(x^2-1)+(y^2-(-2))=16$

Now, we have that:

$h=1\\k=-2\\r=\sqrt{16}=4$

So,

Center: (1,-2)

Radius: 4 units.

Have a nice day!

Note: I have attached a picture for better understanding.

5 0

4 years ago