Volume of Cylinder
= πr²h
= (3.14)(5)²(16)
= 1256 cm³
Volume of Cone
= 1/3πr²h
= 1/3(3.14)(4)²(12)
= 200.96 cm³
Volume of air space
= Volume of Cylinder - Volume of Cone
= 1256 - 200.96
= 1055.04 cm³
≈ 1055 cm³ (nearest whole number)
Answer:
640 students
Step-by-step explanation:
544 divided by 85%= 640
⇒ s = a+b+c2=5+12+132 a + b + c 2 = 5 + 12 + 13 2 = 15 cm.
Area of the base = √s(s−a)(s−b)(s−c)
= √15×10×3×2 15 × 10 × 3 × 2 cm2 = 30 cm2
Start by putting two coins on each side of the scale. If one side is higher, then the light coin must be in that pair (use a second weighing to determine which of that pair is the lightest.)
If the initial weighing shows the two pairs to be even, discard those four and go to the three others. Put two of the coins on the scale - one on each side. If one side stays higher, that coin is your light one. If however they are equal, the final unweighed coin must be the lighter coin.
(1.5) decimal form (mixed number form= 1/2-1) hope this helps.
