Answer:
96 in
Step-by-step explanation:
If the midpoints of the sides are joined to form the smaller triangle, then the perimeter of the smaller triangle is half the perimeter of the greater triangle, because the sides of the smaller triangle are midlines of the greater triangle. By the triangle's midline theorem, each triangle's midline is half the side to which this midline is parallel.
So, if the perimeter of 6th triangle is 3 inches, then the perimeter of 5th triangle is 6 inches, the perimeter of 4th triangle is 12 inches, the perimeter of 3rd triangle is 24 in, the perimeter of 2nd triangle is 48 in and the perimeter of the initial triangle is 96 in
We are given that 8 oz of milk requires 15 oz of flour.
To know the amount of flour needed for 15 oz of milk, we will simply use cross multiplication as follows:
amount of flour needed = (15*15) / (8) = 28.125 oz
The cost of each turkey, if each is a smudge that represents some unreadable digit is $0.94
<h3>Cost of each turkey</h3><h3 />
- Total number of turkey bought = 72
- Total cost = $67.9
Cost of each turkey = Total cost / Total number of turkey bought
= 67.9 / 72
= 0.943055555555555
Approximately,
Cost of each turkey = $0.94
Therefore, the cost of each turkey, if each is a smudge that represents some unreadable digit is $0.94
Learn more about unit rate:
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Answer:
-2, 8/3
Step-by-step explanation:
You can consider the area to be that of a trapezoid with parallel bases f(a) and f(4), and width (4-a). The area of that trapezoid is ...
A = (1/2)(f(a) +f(4))(4 -a)
= (1/2)((3a -1) +(3·4 -1))(4 -a)
= (1/2)(3a +10)(4 -a)
We want this area to be 12, so we can substitute that value for A and solve for "a".
12 = (1/2)(3a +10)(4 -a)
24 = (3a +10)(4 -a) = -3a² +2a +40
3a² -2a -16 = 0 . . . . . . subtract the right side
(3a -8)(a +2) = 0 . . . . . factor
Values of "a" that make these factors zero are ...
a = 8/3, a = -2
The values of "a" that make the area under the curve equal to 12 are -2 and 8/3.
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<em>Alternate solution</em>
The attachment shows a solution using the numerical integration function of a graphing calculator. The area under the curve of function f(x) on the interval [a, 4] is the integral of f(x) on that interval. Perhaps confusingly, we have called that area f(a). As we have seen above, the area is a quadratic function of "a". I find it convenient to use a calculator's functions to solve problems like this where possible.
I think the answer is 1 1/8
