All categories

3 years ago

An ice-cream factory makes 250 quarts of ice-cream in 2 hrs. how many could be made in 36 hrs

2 answers:

Nutka1998 [239]3 years ago

8 0

Find the unit rate of this scenario. 250/2 = 125 quarts per hour
Now multiply the unit rate by the new amount. 36*125 = 4500

Add the units

4,500 quarts in 36 hours.

amid [387]3 years ago

6 0

First you multiply 125 because thats what the machine makes in 1 hour and 125+125=250 so multiply 36 by 125 and that equals 4,500. Answer:4,500

You might be interested in

Two friends are playing with water balloons. They each start at the bucket of balloons and walk in opposite directions before to

oksian1 [2.3K]

Answer:

Step-by-step explanation:

because is joy walked 14 steps and her friend walks 5 steps the answer is 19 steps 14+5=19

6 0

1 year ago

Last year there were 520 students enrolled at Olsen Middle School . This year there are 572 students enrolled. What is the perce

RSB [31]

Answer:

10%

Step-by-step explanation:

We have procent:

520 —-> 100%

572 ——> x%

So, it is:

520*x=572*100

X=57200/520=110%

110%-100%=10%

6 0

3 years ago

Which fraction is between 3/20 and 7/10

slavikrds [6]

5/15 depending on what the answers are

8 0

3 years ago

Find the domain of the Bessel function of order 0 defined by [infinity]J0(x) = Σ (−1)^nx^2n/ 2^2n(n!)^2 n = 0

Snowcat [4.5K]

Answer:

Following are the given series for all x:

Step-by-step explanation:

Given equation:

$\bold{J_0(x)=\sum_{n=0}^{\infty}\frac{((-1)^{n}(x^{2n}))}{(2^{2n})(n!)^2}}\\$

Let the value a so, the value of $a_n$ and the value of $a_(n+1)$ is:

$\to a_n=\frac{(-1)^2n x^{2n}}{2^{2n}(n!)^2}$

$\to a_{(n+1)}=\frac{(-1)^{n+1} x^{2(n+1)}}{2^{2(n+1)}((n+1))!^2}$

To calculates its series we divide the above value:

$\left | \frac{a_(n+1)}{a_n}\right |= \frac{\frac{(-1)^{n+1} x^{2(n+1)}}{2^{2(n+1)}((n+1))!^2}}{\frac{(-1)^2n x^{2n}}{2^{2n}(n!)^2}}\\\\$

$= \left | \frac{(-1)^{n+1} x^{2(n+1)}}{2^{2(n+1)}((n+1))!^2} \cdot \frac {2^{2n}(n!)^2}{(-1)^2n x^{2n}} \right |$

$= \left | \frac{ x^{2n+2}}{2^{2n+2}(n+1)!^2} \cdot \frac {2^{2n}(n!)^2}{x^{2n}} \right |$

$= \left | \frac{ x^{2n+2}}{2^{2n+2}(n+1)^2 (n!)^2} \cdot \frac {2^{2n}(n!)^2}{x^{2n}} \right |\\\\= \left | \frac{x^{2n}\cdot x^2}{2^{2n} \cdot 2^2(n+1)^2 (n!)^2} \cdot \frac {2^{2n}(n!)^2}{x^{2n}} \right |\\\\$

$= \frac{x^2}{2^2(n+1)^2}\longrightarrow 0$ for all x

The final value of the converges series for all x.

8 0

3 years ago

Two containers designed to hold water are side by side, both in the shape of a cylinder. Container A has a radius of 11 feet and

Inessa [10]

Answer: The percentage ≅ 48.4%

Step-by-step explanation:

* Lets revise how to find the volume of a container shaped cylinder

- The volume of any container = area of its base × its height

- The base of the cylinder is a circle, area circle = 2 π r,

where r is the length of its radius

* In container A:

∵ r = 13 feet , height = 13 feet

∴ Its volume = π (13)² × (13) = 2197π feet³

* In container B:

∵ r = 9 feet , height = 14 feet

∴ Its volume = π (9)² × (14) = 1134π feet³

* So to fill container B from container A, you will take from

container A a volume of 1134π feet³

- The volume of water left in container A = 2197π - 1134π = 1063π feet³

* To find the percentage of the water that is full after pumping

is complete, divide the volume of water left in container A

by the original volume of the container multiplied by 100

∴ The percentage = (1063π/2197π) × 100 = 48.3841 ≅ 48.4%

8 0

3 years ago