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3 years ago

8

What is the approximate value of this logarithmic expression?

2 answers:

mestny [16]3 years ago

8 0

Answer:

$log_8{24} = 1.53$

Step-by-step explanation:

Given

$log_8{24}$

Required

Solve:

Apply the following law of logarithm:

$log_a{b} = \frac{log\ b}{log\ a}$

So, we have:

$log_8{24} = \frac{log\ 24}{log\ 8}$

Using calculator, we have:

$log_8{24} = \frac{1.38021124171}{0.90308998699}$

$log_8{24} = 1.52832083358$

Approximate

$log_8{24} = 1.53$

GarryVolchara [31]3 years ago

4 0

Answer:

1.53

Step-by-step explanation:

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2 years ago

Use the equation below to answer the question.

JulijaS [17]

Answer:

The signa notation to represent the first five ten f(x) is given by $f(x)=\sum\limits^{5}_{n=1}a_n$

Step-by-step explanation:

Given sequence is -5, -9, 13...

Let f(x) be the given sequence and is denoted by

$f(x)=\{-5,-9,-13,...\}$

Let the first term be $a_1, 2^{\textrm{nd}}$ term be $a_3,...$

ie, $a_1=-5,a_2=-9, a_3=-13,...$

To find the common difference d:

$d=a_2-a_1$

$=-9-(-5)$

$=-9-(+5)$

$d=-4$

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$=-13-(-9)$

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$d=-4$

Therefore the common difference d is -4 for given sequence f(x) with $a_1=-5$ and d=-4, the seqence f(x) is an arithmetic sequence

By defintion of arithmetic sequence

$a_n=a+(n-1)d\hfill(1)$

Now to find $a_4, a_5$ :

put n=4 in equation (1)

$a_4=a+(4-1)d$

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$=-5-12$

$a_4=-17$

in equation (1)

$a_5=a+(5-1)d$

$a_5=-5+(4)(-4)$ [since a=-5, d=-4]

$=-5-16$

$a_5=-21$

Therefore $a_4=-17$ and $a_5=-21$

Therefore $f(x)=\{-5,-9,-13,-17,-21,...\}$

Now to represent the sum of the first five terms of f(x) using sigma notation as below

$f(x)=\sum_{n=1}^5 a_n$

where $\sum_{n=1}^5 a_n=a_1+a_2+a_3+a_4+a_5$

$-5-9-13-17-21$

$\sum_{n=1}^5 a_n=-65$

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4 years ago

The length of a rectangle is six more than double the width. If the perimeter is 84 inches, find the dimensions.

EleoNora [17]

Answer:

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3 years ago

Sara compra 3 naranjas a Q 2.00 cada una. Compra un melón a

yanalaym [24]

Respuesta:

29.00

Explicación:

una naranja 3.00

un melón 12.00

una manzana 2.00 (porque una docena equivale 12 artículos; 24/12 es 2)

tres naranjas 3(3.00) = 9.00

un melón 12.00

cuatro manzanas 4(2.00) = 8.00

9.00 +12.00 +8.00

29.00

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3 years ago