For this simulation, there are 5 numbers that we can draw. One of the numbers will result in seeing the groundhog. (1/5 or 0.20) To find the probability that Jay will see the groundhog 4 years in a row, we would use the following equation: 1/5•1/5•1/5•1/5
We would multiply the odds of getting a certain outcome by the number of time we want that outcome.
The odds that Jay will see the groundhog for the next for years is 0.0016, or .16%.
Step-by-step explanation:
A
Since the constant has been moved to the left side, you can move on to the next step which is adding (b/2)² to both sides of the equation.
h² + 14h + (14/2)² = -31 + (14/2)²
Simplify the parenthesis and exponent.
h² + 14h + 7² = -31 + 7²
h² + 14h + 49 = -31 + 49
h² + 14h + 49 = 18
Factor the expression of the left.
(h + 7)(h + 7) = 18
Take the square root of both sides.
√(h + 7)(h + 7) = ± √9 • 2
(h + 7) = ± 3√2
h + 7 = ± 3√2
Subtract 7 from both sides.
You solutions are:
h = -7 + 3√2 → -2.7573 → -2.76
h = -7 - 3√2 → -11.2426 → -11.24
4 because 1/4 is basically dividing by 4
Answer:
12
Step-by-step explanation:
When the numerators are the same, the denominator that is bigger has a lesser value. In this case, the inequality > shows that 
is bigger than the fraction next to it so in order to find a fraction that is lesser in value than , we need to find a denominator that is <u>more than 10</u>, since 10 is the denominator of the first fraction. The only number more than 10 in the options is 12, so 12 is the answer.
