What is the question? If you want to know how to graph this equation, it's usually easiest to start with the intercepts, i.e., the points where the line crosses the axes.

y = ½x + 3 tells you that the line crosses the y-axis at (0,3), so plot that point.

Then let y = 0 and solve for x.

0 = ½x + 3

x = 6

The line crosses the x-axis at (6,0), so plot that point as well.

Then draw the line passing through those two points.

8 0

3 years ago

What is the medicine Allopurinol do?

MrRa [10]

Allopurinol:

- Xanthine oxidase inhibitor

- Prevents the buildup of uric acid

- Prevents urinary/bladder/kidney stones

5 0

3 years ago

Graph a line with a slope of 1/4 that contains the point (6, 3).

Semenov [28]

Answer:

The graph in the attached figure

Step-by-step explanation:

we know that

The equation of a line in point slope form is

$y-y1=m(x-x1)$

we have

$(x_1,y_1)=(6,3)$

$m=\frac{1}{4}$

substitute

$y-3=\frac{1}{4}(x-6)$

The easiest way to graph a line is to calculate the intercepts

The x-intercept is the value of x when the value of y is equal to zero

For y=0

$0-3=\frac{1}{4}(x-6)$

$-12=(x-6)$

$x=-12+6=-6$

The x-intercept is the point (-6,0)

The y-intercept is the value of y when the value of x is equal to zero

For x=0

$y-3=\frac{1}{4}(0-6)$

$y-3=-\frac{3}{2}$

$y=-\frac{3}{2}+3$

$y=1.5$

The y-intercept is the point (0,1.5)

Plot the intercepts and join the points to graph the line

(-6,0) and (0,1.5)

The graph in the attached figure

8 0

3 years ago