Proportional and linear functions are almost identical in form. The only difference is the addition of the “b” constant to the linear function. Indeed, a proportional relationship is just a linear relationship where b = 0, or to put it another way, where the line passes through the origin
Answer:
A :-) Given -
perimeter = 65 inches
Side ‘a’ = 2x
Side ‘b’ = 3 1 by 4x + 1
Solution -
Perimeter = 65
= a + b = 65
= 2x + 3 1 by 4x + 1 = 65
( 3 1 by 4 = 4 x 3 + 1 = 12 + 1 by 4
= 13 by 4 )
= 2x + 13 by 4x + 1 = 65
= 2x + 13 by 4x = 65 - 1
= 2x + 13 by 4x = 64
= 15 by 4 x = 64
= x = 64 x 4 by 15
= x = 256 by 15
= x = 17.06
.:. The value of x = 17.06.
Answer:
12
Step-by-step explanation:
Given: Diagonal of square= ![3\sqrt{2}](https://tex.z-dn.net/?f=3%5Csqrt%7B2%7D)
To find the perimeter of square, we need to find the length of sides of square.
∴ Using the formula of diagonal to find side of square.
Formula; ![Diagonal= s\sqrt{2}](https://tex.z-dn.net/?f=Diagonal%3D%20s%5Csqrt%7B2%7D)
Where, s is side of square.
⇒ ![3\sqrt{2} = s\sqrt{2}](https://tex.z-dn.net/?f=3%5Csqrt%7B2%7D%20%3D%20s%5Csqrt%7B2%7D)
Dividing both side by √2
⇒![s= \frac{3\sqrt{2} }{\sqrt{2} }](https://tex.z-dn.net/?f=s%3D%20%5Cfrac%7B3%5Csqrt%7B2%7D%20%7D%7B%5Csqrt%7B2%7D%20%7D)
∴![s= 3](https://tex.z-dn.net/?f=s%3D%203)
Hence, Length of side of square is 3.
Now, finding the perimeter of square.
Formula; ![Perimeter= 4s](https://tex.z-dn.net/?f=Perimeter%3D%204s)
⇒![Perimeter= 4\times 3](https://tex.z-dn.net/?f=Perimeter%3D%204%5Ctimes%203)
∴ ![Perimeter= 12](https://tex.z-dn.net/?f=Perimeter%3D%2012)
Hence, Perimeter of square is 12.
Answer:
Either B or D.
Step-by-step explanation:
I consider both options valid. It all depends on how the employer is keeping track of time, ie if the pay "ticks" every 60 minutes, or an employee is allowed to clock in half hours.
Will I be able to work 30 and a half hour for example? If I'm allowed to, D.
If I have to work multiple of 60 minutes, B.