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VMariaS [17]
2 years ago
14

A dog is fed 3 1/2 cups of food. A puppy is fed 3/5 of that. How much is the puppy fed?

Mathematics
1 answer:
LUCKY_DIMON [66]2 years ago
4 0

Answer:

  • 9 puppies can be fed.

Step-by-step explanation:

<u>Given that</u>:

  • A dog is fed 312 cups of food.
  • A puppy is fed 35 of that.

<u>To Find</u>:

  • How much is the puppy fed?

<u>Let us assume</u>:

  • x puppies can be fed.

<u>Finding the number of puppy</u>:

Puppy : Food = Puppy : Food

⟶ 35 : 1 = 312 : x

⟶ 35/1 = 312/x

Cross multiplication.

⟶ 35x = 312

⟶ x = 312/35

⟶ x = 9 (approx.)

<u>Hence</u>,

  • 9 puppies can be fed.

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Step-by-step explanation:

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3 years ago
How many hats did the knitter who sold 5 scarves sell?
Angelina_Jolie [31]
Zero, if she sold 5 scarves & it doesn’t say anything about hats
3 0
3 years ago
NO LINKS!!
dexar [7]

Answer: Anything between 0 and 10, excluding both endpoints.

In terms of symbols we can say 0 < w < 10 where w is the width.

===================================================

Explanation:

You could do this with two variables, but I think it's easier to instead use one variable only. This is because the length is dependent on what you pick for the width.

w = width

2w = twice the width

2w-5 = five less than twice the width = length

So,

  • width = w
  • length = 2w-5

which lead to

area = length*width

area = (2w-5)*w

area = 2w^2-5w

area < 150

2w^2 - 5w < 150

2w^2 - 5w - 150 < 0

To solve this inequality, we will solve the equation 2w^2-5w-150 = 0

Use the quadratic formula. Plug in a = 2, b = -5, c = -150

w = \frac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\w = \frac{-(-5)\pm\sqrt{(-5)^2-4(2)(-150)}}{2(2)}\\\\w = \frac{5\pm\sqrt{1225}}{4}\\\\w = \frac{5\pm35}{4}\\\\w = \frac{5+35}{4} \ \text{ or } \ w = \frac{5-35}{4}\\\\w = \frac{40}{4} \ \text{ or } \ w = \frac{-30}{4}\\\\w = 10 \ \text{ or } \ w = -7.5\\\\

Ignore the negative solution as it makes no sense to have a negative width.

The only practical root is w = 10.

If w = 10 feet, then the area = 2w^2-5w results in 150 square feet.

----------------------

Based on that root, we need to try a sample value that is to the left of it.

Let's say we try w = 5.

2w^2 - 5w < 150

2*5^2 - 5*5 < 150

25 < 150 ... which is true

This shows that if 0 < w < 10, then 2w^2-5w < 150 is true.

Now try something to the right of 10. I'll pick w = 15

2w^2 - 5w < 150

2*15^2 - 5*15 < 150

375 < 150 ... which is false

It means w > 10 leads to 2w^2-5w < 150  being false.

Therefore w > 10 isn't allowed if we want 2w^2-5w < 150 to be true.

4 0
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Write an equation for the both term of the arithmetic sequence 30,26,22,18
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Answer:

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Step-by-step explanation:

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The students on the right hand side had better overall results

There were less people on the left hand side of the room this affects the average even with the right hand side having two zeros, another thing which the left hand side didn’t have.

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