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frosja888 [35]
2 years ago
15

Design an instructional activity that could help learner's recognise the decimal fractions can be applied across environmental s

ituation relating to activities in real-life
​
Mathematics
1 answer:
lapo4ka [179]2 years ago
7 0

An instructional activity that could help learners recognize fractions includes an analog clock, fraction strips, and pattern block.

<h3>What is an instructional activity?</h3>

Instructional activities are routine segments of instruction that show how the teacher and students will participate and interact with materials and content.

An instructional activity that could help learners recognize fractions includes an analog clock, fraction strips, and pattern block. For example, if one wants to teach students about fractional parts that are divided equally into twelfths, the analog clock can be ideal.

Learn more about fractions on;

brainly.com/question/78672

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It adds 13
11 + 13 =24
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3 years ago
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John has two jobs. For daytime work at a jewelry store he is paid
djyliett [7]

Given Information:

John's mean monthly commission = μ = $10,000

Standard deviation of monthly commission = σ =  $2,000

Answer:

P(9,000 < X < 11,000) = 0.383\\\\P(9,000 < X < 11,000) = 38.3 \%

The probability that John's commission from the jewelry store is  between $9,000 and $11,000 is 38.3%

Step-by-step explanation:

What is Normal Distribution?

We are given a Normal Distribution, which is a continuous probability distribution and is symmetrical around the mean. The shape of this distribution is like a bell curve and most of the data is clustered around the mean. The area under this bell shaped curve represents the probability.  

We want to find out the probability that John's commission from the jewelry store is  between $9,000 and $11,000?

P(9,000 < X < 11,000) = P( \frac{x - \mu}{\sigma} < Z < \frac{x - \mu}{\sigma} )\\\\P(9,000 < X < 11,000) = P( \frac{9,000 - 10,000}{2,000} < Z < \frac{11,000 - 10,000}{2,000} )\\\\P(9,000 < X < 11,000) = P( \frac{-1,000}{2,000} < Z < \frac{1,000}{2,000} )\\\\P(9,000 < X < 11,000) = P( -0.5 < Z < 0.5 )\\\\P(9,000 < X < 11,000) = P( Z < 0.5 ) - P( Z < -0.5 ) \\\\

The z-score corresponding to 0.50 is 0.6915

The z-score corresponding to -0.50 is 0.3085

P(9,000 < X < 11,000) = 0.6915 - 0.3085 \\\\P(9,000 < X < 11,000) = 0.383\\\\P(9,000 < X < 11,000) = 38.3 \%

Therefore, the probability that John's commission from the jewelry store is  between $9,000 and $11,000 is 38.3%

How to use z-table?

Step 1:

In the z-table, find the two-digit number on the left side corresponding to your z-score. (e.g 1.4, 2.2, 0.5 etc.)

Step 2:

Then look up at the top of z-table to find the remaining decimal point in the range of 0.00 to 0.09. (e.g. if you are looking for 0.50 then go for 0.00 column)

Step 3:

Finally, find the corresponding probability from the z-table at the intersection of step 1 and step 2.

4 0
3 years ago
Noah and his children went into a grocery store and where they sell apples for $1
Black_prince [1.1K]

Answer:

8

Step-by-step explanation:

Since Noah has decided to buy 4 apples, that means he has decided to spend $4 on apples. Deducting that from $20, you are left with $16. Divide this total by the cost of each mango, $2, and you get the result as 8 mangos.

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3 years ago
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zepelin [54]
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Then add both numerators
\frac{5}{10}  +  \frac{4}{10}  =  \frac{9}{10}
Your final answer should be
\frac{9}{10}
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-64, -50, -45, 28, 34, 65
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3 years ago
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