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blondinia [14]
3 years ago
10

Which problem could the bar diagram represent?

Mathematics
1 answer:
ozzi3 years ago
5 0

Answer:

I think it is A. This image shows a rectangular grid divided in two parts by a vertical line above which number 250 is written in centre. Left side has 182 and right side has question mark.

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If the fourth multiple of 3 is subtracted from the third multiple of 4 what is the difference
anyanavicka [17]
The difference is zero if you aren't insinuating that the term, "multiple" doesn't involve exponential factors.

3•4 = 12
4•3 = 12

12
-12
___
0


However, if you are saying one multiple of 3 involves exponential powers, Then 3^4 is 81 and 4^3 is 64

4^3 = 64

64 - 81 = -17
8 0
2 years ago
Read 2 more answers
Company A charges $107 and allows unlimited mileage.
skad [1K]

Answer:

At mile 3 company A will start charging less.

Step-by-step explanation:

I came to this conclusion by realizing that no matter what company A will always charge $107 so, in theory all we needed to do was get company eight to $108. So having this mind set I created the equation, 65 + .70x  . I continuously kept on changing what was in x until the price was just above Company A's. And the number that got me there was 3.

7 0
2 years ago
Can you help me solve this equation?
dem82 [27]

Sure

Answer:

x = -2

If the steps aren't belong to the lesson that you want, just tell me the lesson title so I can get the answer for you !!!!

...

The steps

Multiply all terms by (x-3)(x+3) and cancel:

x(x+3)+2x(x−3)=18

3x2−3x=18(Simplify both sides of the equation)

3x2−3x−18=18−18(Subtract 18 from both sides)

3x2−3x−18=0

3(x+2)(x−3)=0(Factor left side of equation)

x+2=0 or x−3=0(Set factors equal to 0)

x=−2 or x=3

Check answers. (Plug them in to make sure they work.)

x=−2 (Works in original equation)

x=3 (Doesn't work in original equation)

7 0
2 years ago
PLEASE ANSWER CORRECTLY and show your work! I will give brainliest!
Alenkinab [10]

Answer: The new co-ordinates of A ( 2 ,-6)

Step-by-step explanation:

Type of transformation                                change to co-ordinate point

Vertical translation up 'd' units                  (x,y)→(x , y+d)

Vertical translation down 'd' units             (x,y)→(x , y-d)

Horizontal translation right 'c' units           (x,y)→(x+c , y)

Horizontal translation left 'c' units           (x,y)→(x-c , y)

Reflection over x-axis                               (x,y) →(x , -y)

Reflection over y-axis                               (x,y) →(-x , y)

Given the original vertex A ( -2 ,3)

a) First reflection over x-axis  ( -2 ,3) →(-2 , -3)

b) Vertical translation down '3' units  so it changes (-2 , -3)→(-2 , -3-3)

                        (-2,-3)→(-2 ,-6)

and

c) The Horizontal translation right '4' units

now it changes ( -2 ,-6) → (-2+4,-6)→(2 ,-6)

Final answer:-

The new co-ordinates of A ( 2 ,-6)

3 0
2 years ago
In the equation y = <img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bx%7D%7B3%7D%20" id="TexFormula1" title=" \frac{x}{3} " alt="
Likurg_2 [28]
                              x
Just rewrite   <span>y = ---- as    y = (1/3)x.  The unit rate is 1/3.
                              3</span>
7 0
3 years ago
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