1) C(2
2) A(-4
3) B(4+(2+1)=4+2)+1
4) D(3(2x4)=(3x2)4
5) A(5+6=6+5
6) C(12x1=1x12
7) D(Exponents
8) A(addition and subtraction
9) A(55
10) B(19
Answer:
That is a picture of the answer and the explanation
Step-by-step explanation:
Using the monthly payments formula, it is found that a car with a value of at most $25,293.
<h3>What is the monthly payment formula?</h3>
It is given by:

In which:
- n is the number of payments.
In this problem, we have that the parameters are given as follows:
A = 400, n = 70, r = 0.035.
Hence:
r/12 = 0.035/12 = 0.002917.
Then we have to solve for P to find the maximum value of the car.


![P = \frac{400[(1.002917)^{70}-1]}{0.002917(1.002917)^{70}}](https://tex.z-dn.net/?f=P%20%3D%20%5Cfrac%7B400%5B%281.002917%29%5E%7B70%7D-1%5D%7D%7B0.002917%281.002917%29%5E%7B70%7D%7D)
P = $25,293.
More can be learned about the monthly payments formula at brainly.com/question/26267630
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