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IRINA_888 [86]
3 years ago
6

Lara is putting lace trim around the border of a circular tablecloth. The tablecloth has a diameter of 1.2 meters. What is the l

ength of the lace she needs? Round to the nearest tenth of a meter.
Mathematics
1 answer:
mylen [45]3 years ago
6 0

Answer:

3.8m

Step-by-step explanation:

Since Lara is putting lace trim around the border of a circular tablecloth, by the time she finishes she has covered the circumference.

The circumference of a circle is calculated using:

C=\pi \: d

where d is the diameter of the circle.

It was given that the diameter of the circular table cloth is 1.2 meters.

C=3.14 \times 1.2

C=3.768

Therefore the length of the lace she needed is 3.8m

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Please help me out with thissss
vova2212 [387]

Answer:

Step-by-step explanation:

From table 1,

f(x) = bˣ

For x = -1,

f(-1) = 0.5

0.5 = (b)⁻¹

b = \frac{1}{0.5}

b = 2

For x = 1.585,

f(1.585) = 3

3 = 2^{1.585}

3 = 2^{1}\times2^{0.585}

2^{0.585}=\frac{3}{2}

2^{0.585}=1.5

For x = 2.585,

f(2.585) = 2^{2.585}

             = 2^{2}\times 2^{0.585}

             = 4 × 1.5 [Since, 2^{0.585}=1.5]

             = 6

From table 2,

g(x) = \text{log}_b(x)

For x = 0.5,

g(0.5) = -1

-1 = \text{log}_b(0.5)

b⁻¹ = 0.5

b = 2

For x = 2,

g(2) = 1

1 = \text{log}_2(2)

For x = 6,

g(6) = 2.585

2.585 = \text{log}_2(6)

2.585 = \text{log}_2(2\times 3)

2.585 = \text{log}_2(2)+\text{log}_2(3)

2.858 - 1 = \text{log}_2(3)

\text{log}_2(3)=1.585

For x = 3,

g(3) = \text{log}_2(3)

g(3) = 1.585

8 0
2 years ago
What is the value of m in the figure? In this diagram ABD~BCD
Margaret [11]

Answer:

<h2>D.  √136</h2><h2 />

Step-by-step explanation:

see attached sketch

7 0
2 years ago
Find the slope of each line​
MA_775_DIABLO [31]

Answer:

odading mang oleh rasanya

6 0
2 years ago
Select True or False from each pull-down menu, depending on whether the corresponding statement is true or false.
Schach [20]

Answer:

1) FALSE

2) FALSE

3) TRUE

4) TRUE

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Part 1

The mean and standard deviation of a normally distributed random variable which has been standardized are one and zero, respectively.

The mean and the deviation for  the normal standard distribution are:

\mu=0, \sigma =1

So then that's FALSE.

Part 2

Using the standard normal curve, the z−score representing the 10th percentile is 1.28.

We are looking for a value a, that satisfy this:

P(X>a)=0.90   (a)

P(X   (b)  

We can find a z value that satisfy the condition with 0.10 of the area on the left and 0.90 of the area on the right it's z=-1.28. On this case P(Z<-1.28)=0.10 and P(Z>-1.28)=0.90

So that's FALSE.

Part 3

Let z1 be a z−score that is unknown but identifiable by position and area. If the symmetrical area between −z1 and +z1 is 0.9544, the value of z1 is 2.0

If we find this probability:

P(-2.0< Z

So on this case we can approximate to 0.9544. And that's TRUE.

Part 4

Using the standard normal curve, the z−score representing the 75th percentile is 0.67.

We are looking for a value a, that satisfy this:

P(X>a)=0.25   (a)

P(X   (b)  

We can find a z value that satisfy the condition with 0.75 of the area on the left and 0.25 of the area on the right it's z=0.67. On this case P(Z<0.67)=0.75 and P(Z>0.67)=0.25

So that's TRUE.

3 0
3 years ago
PLLLLLLLEAAAASSE hELPPPPP i WILL GIVE BRAINLIEST TO THE FIRST PERSON WHO ANSWERS CORRECTY!!!!
iren [92.7K]

Hello there,

The answer will be <u>1</u><u>5</u><u> </u><u>students.</u>

<h3>Step-by-step explanation:-</h3>

We will solve the equation as follows:-

First add the total of the students in band and chorus -

→ 70 + 95 = 165

Then subtract the previously got number with given number of chorus students:-

→ 165 - 150 = 15

So, there are <u>15 students</u> who are there in both band and chorus.

✍️ <em>By </em><em>Benjemin</em> ☺️

5 0
2 years ago
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