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dalvyx [7]
3 years ago
7

please hurry write a vector equation of a line that passes through p(-4,12) and is parallel to q=(14,-8)

Mathematics
1 answer:
Kobotan [32]3 years ago
5 0

The line containing the vector <em>q</em> can be obtained by scaling <em>q</em> by an arbitrary scalar <em>t</em>. To make this line pass through the point <em>p</em>, translate this line by a vector <em>p</em> pointing from the origin to <em>p</em>.

So the line we want has equation

<em>r</em>(<em>t</em>) = <em>q</em><em>t</em> + <em>p</em> = (14, -8)<em>t</em> + (-4, 12) = (14<em>t</em> - 4, 12-8<em>t</em>)

where <em>t</em> is any real number.

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Log In a survey of a town, 63% of residents own a car, 20% of residents own a truck, and 4% of residents own both a car and a tr
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Answer:

6%

Step-by-step explanation:

Let T= truck

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We are looking for the probability that someone owns a truck given that they own a car

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Five distinct numbers are randomly distributed to players numbers 1 through 5. Whenever two playerscompare their numbers, the on
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Answer:

Observe that the first and the second player have equal probability to get any of number. Using the principle of that symmetry, we have that  

P(X=0)=\frac{1}{2}

<u>Event X = 1 </u>means that the first player has got greater number than the second player, but not than the third player. So, choose any three numbers out of five of them and say that the minimal number out of these three goes to the second player, mean number to the first one and the largest to the third one. Permute remaining two numbers on remaining two people. Hence

P(X=1)=\frac{1}{6}

<u>Event X = 2</u> means that the first player has got greater number than the second and the third player, but not than the fourth player. So, choose any four numbers out of five of them and say that the minimal number and the next minimal out of these four go to the second and the third player (and permute them), third number to the first one and the largest to the fourth player. Give remaining number to the last person. Hence

P(X=2)=\frac{1}{12}

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P(X=3)=\frac{1}{20}

<u>Event X = 4</u> means basically the first player has won all the battles i.e, he has got the greatest number. Hence

P(X=4)=\frac{1}{5}

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