Question

please hurry write a vector equation of a line that passes through p(-4,12) and is parallel to q=(14,-8)

Answer 1

The line containing the vector q can be obtained by scaling q by an arbitrary scalar t. To make this line pass through the point p, translate this line by a vector p pointing from the origin to p.

So the line we want has equation

r(t) = qt + p = (14, -8)t + (-4, 12) = (14t - 4, 12-8t)

where t is any real number.