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Bad White [126]
3 years ago
15

If tan theta= -0.87, find cot

Mathematics
1 answer:
ale4655 [162]3 years ago
8 0

Answer:

Step-by-step explanation:

cot(\frac{\pi }{2} -\theta)=tan \theta=-0.87

or second method

\cot(\frac{\pi }{2} -\theta)=\frac{1}{\tan(\frac{\pi }{2} -\theta)} =\frac{1}{\frac{\tan\frac{\pi }{2} -\tan \theta}{1+\tan \frac{\pi }{2 } \tan \theta} } =\frac{1+\tan\frac{\pi }{2} \tan \theta}{\tan\frac{\pi }{2} -\tan \theta} \\(divide~the~numerator~and~denominator~by~\tan\frac{\pi }{2} )

=\frac{\cot\frac{\pi }{2} +\tan\theta}{1-\cot\frac{\pi }{2} \tan\theta} \\=\frac{0+\tan \theta }{1-0*\tan\theta} \\=\tan \theta\\=-0.87

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Ira Lisetskai [31]

Answer: See the step by step explanation.

Step-by-step explanation:

a) First, Let P(n) be the statement that n! < n^n

where n ≥ 2 is an integer (This is because we want the statement of P(2).

In this case the statement would be (n = 2): P(2) = 2! < 2^2

b) Now to prove this, let's complet the basis step:

We know that 2! = 2 * 1 = 2

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Therefore: 2 < 4

c)  For this part, we'll say that the inductive hypothesis would be assuming that k! < k^k for some k ≥ 1

d) In this part, the only thing we need to know or prove is to show that P(k+1) is also true, given the inductive hypothesis in part c.

e) To prove that P(k+1) is true, let's solve the inductive hypothesis of k! < k^k:

(k + 1)! = (k + 1)k!  

(k + 1)k!  < (k + 1)^k  < (k + 1)(k + 1)^k

Since k < k+1 we have:

= (k + 1)^k+1

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6 0
2 years ago
Which symbol would make the number sentence true 8/11 ? 0.73
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Step-by-step explanation:

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6 0
3 years ago
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NeX [460]

9514 1404 393

Answer:

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Step-by-step explanation:

Angle E is congruent to angle C, so is the value required to make the sum of angles in triangle ABC be 180°.

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Answer:   x ≤ 3

Step-by-step explanation:

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Second is not linear, but rather exponential.

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2 years ago
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