Three and six tenths. The decimal point is always expressed as "and." the digit after the decimal point is always expressed by tenths.
We let x the distance traveled by Car A and y the distance traveled by car B. The speed of car A can be represented as x/2.4 and for Car B is y/4. From the statement given, we can write an equation relating the speed of both cars.
x/2.4 = 22 + y/4
Since y = x, then:
x/2.4 = 22 + x/4
Solving for x, we obtain:
x= 132 meters traveled by both cars
Therefore, Car A has a speed of 55 mph.
Answer:
ln(2) + 3ln(a) - 4ln (b)
Step-by-step explanation:
ln(2a^3 /b^4)
We know that ln(x/y) = ln (x) - ln y
ln(2a^3 ) - ln (b^4)
We know that ln (xy) = ln x + ln y
ln(2) + ln(a^3 ) - ln (b^4)
We know that ln(x^y) = y ln (x)
ln(2) + 3ln(a) - 4ln (b)
