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maria [59]
3 years ago
10

Ann is ordering an ice cream dessert. She must order a size, a flavor of ice cream, and a topping. There are 3 sizes, 1 flavor,

and 4toppings to choose from. How many different ice cream desserts could she order?
Mathematics
1 answer:
tensa zangetsu [6.8K]3 years ago
3 0

Answer:

Only 1 flavour ??

Only 1 flavour ??anyway ....

Only 1 flavour ??anyway ....number of different ice cream desserts

desserts= 3 x 1 x 4

= 12

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Soft-drink cans are filled by an automated filling machine and the standard deviation is 0.5 fluid ounces assume that the fill v
evablogger [386]
A.) For n independent variates with the same distribution, the standard deviation of their mean is the standard deviation of an individual divided by the square root of the sample size: i.e. s.d. (mean) = s.d. / sqrt(n)
Therefore, the standard deviation of of the average fill volume of 100 cans is given by 0.5 / sqrt(100) = 0.5 / 10 = 0.05

b.) In a normal distribution, P(X < x) is given by P(z < (x - mean) / s.d).
Thus, P(X < 12) = P(z < (12 - 12.1) / 0.05) = P(z < -2) = 1 - P(z < 2) = 1 - 0.97725 = 0.02275

c.) Let the required mean fill volume be u, then P(X < 12) = P(z < (12 - u) / 0.05) = 1 - P(z < (u - 12) / 0.05) = 0.005
P(z < (u - 12) / 0.05) = 1 - 0.005 = 0.995 = P(z < 2.575)
(u - 12) / 0.05 = 2.575
u - 12 = 2.575 x 0.05 = 0.12875
u = 12 + 0.12875 = 12.12875
Therefore, the mean fill volume should be 12.12875 so that the probability that the average of 100 cans is below 12 fluid ounces be 0.005.

d.) Let the required standard deviation of fill volume be s, then P(X < 12) = P(z < (12 - 12.1) / s) = 1 - P(z < 0.1 / s) = 0.005
P(z < 0.1 / s) = 1 - 0.005 = 0.995 = P(z < 2.575)
0.1 / s = 2.575
s = 0.1 / 2.575 = 0.0388
Therefore, the standard deviation of fill volume should be 0.0388 so that the probability that the average of 100 cans is below 12 fluid ounces be 0.005.

e.) Let the required number of cans be n, then P(X < 12) = P(z < (12 - 12.1) / (0.5/sqrt(n))) = 1 - P(z < (12.1 - 12) / (0.5/sqrt(n))) = 0.01
P(z < 0.1 / (0.5/sqrt(n))) = 1 - 0.01 = 0.99 = P(z < 2.327)
0.1 / (0.5/sqrt(n)) = 2.327
0.5/sqrt(n) = 0.1 / 2.327 = 0.0430
sqrt(n) = 0.5/0.0430 = 11.635
n = 11.635^2 = 135.37
Therefore, the number of cans that need to be measured such that the average fill volume is less than 12 fluid ounces be 0.01

8 0
3 years ago
I dont understand this
MrRa [10]

Answer: First option.

Step-by-step explanation:

You need to remember the following Trigonometric Identity:

cos\alpha =\frac{adjacent}{hypotenuse}

In this case, you can identify in the figure that:

\alpha =35\°\\adjacent=9\\hypotenuse=x

Then you must substitute these values into cos\alpha =\frac{adjacent}{hypotenuse}:

cos(35\°) =\frac{9}{x}

Finally, you need to solve for "x" in order to find its value. This is:

(x)(cos(35\°))=9\\\\x=\frac{9}{cos(35\°)}\\\\x=10.98

Rounding the result to the nearest tenth, you get:

x\approx11

8 0
3 years ago
Find the slope of the line for the equation 3y=4. Please explain
eduard
Y=4/3 because if 3 goes to rhs is becomes divided by the number on the rhs so answer is 4/3
6 0
3 years ago
Of the 200 cows in the herd, five-eighths grazed in the field. The rest slept near the barn. How many grazed in the field and ho
agasfer [191]

Answer:

125 barn 75 sleeping

Step-by-step explanation:

5/8 of 200 cows

of means multiply

5/8 x 200 = 1000/8 = 125

125 cows grazing

200-125 = rest of cows

75 = rest of cows sleeping

7 0
2 years ago
What did I do wrong. I thought it was 15
CaHeK987 [17]
Its not 15 isnt it 10
3 0
3 years ago
Read 2 more answers
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