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3 years ago

Find the molarity of a solution in which 0.99 mol of NaCl are dissolved in 2.5 L of solution.

Chemistry

1 answer:

rusak2 [61]3 years ago

3 0

Answer:

0.369M

Explanation:

$\boxed{Molarity = mole \div volume}$

☆ Volume has to be in litres

Molarity of solution

= 0.99 ÷2.5

= 0.369 M

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4 years ago

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Explanation:

For a:

Dissolution reaction is defined as the reaction in which a solid compound gets dissolved in water to form aqueous solution.

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$Na_2CO_3(s)\rightarrow Na_2CO_3(aq.)$

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$Na_2CO_3(aq.)\rightarrow 2Na^+(aq.)+CO_3^{3-}(aq.)$

For b:

Now, the anion formed which is $CO_3^{2-}$ reacts with water to form conjugate acid.

The chemical equation for the reaction of anion with water follows:

$CO_3^{2-}(aq.)+H_2O(l)\rightarrow OH^-(aq.)+HCO_3^-(aq.)$

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3 years ago