Image result for What happens to sodium chloride when it dissolves in water
Explanation: On addition to water the Na+ section of NaCl is attracted to the oxygen side of the water molecules, while the Cl- side is attracted to the hydrogens' side of the water molecule. This causes the sodium chloride to split in water, and the NaCl dissolves into separate Na+ and Cl- atoms
Question 3
Explanation:
answer -A /A chemical reaction happens when substances break apart or combine to form one or more new substances. New substances form when bonds break and new bonds form. The chemical properties of the new substances are different from those of the original substances. ... Some chemical reactions produce a precipitate.
answer- B /Chemical reactions occur when chemical bonds between atoms are formed or broken. The substances that go into a chemical reaction are called the reactants, and the substances produced at the end of the reaction are known as the products
Answer: C. Electrochemical cells involve oxidation-reduction reactions.
Explanation: Oxidation occurs at the anode, and reduction occurs at the cathode.
The ph after 17.0 ml of 0.15 m Koh has been added to 15 ml of 0.20 m hclo4 is <u>3.347</u>.
Titration is a commonplace laboratory technique of quantitative chemical analysis to determine the attention of an identified analyte. A reagent, termed the titrant or titrator, is ready as a trendy answer of recognized awareness and extent.
<u>Calculation:-</u>
Normality of acid Normality of base
= nMV nMV
= 1 × 0. 15 × 0.017 1 × 0. 20 ×0.015 L
= 2.55 × 10⁻³ = 3 × 10⁻³
The overall base will be high
net concentration = 3× 10⁻³ - 2.55 × 10⁻³
= 0.45 × 10⁻³
= 4.5× 10⁻⁴
pH = -log[4.5 × 10⁻⁴]
= 4 - log4.4
= <u>3.347</u>
A titration is defined as 'the manner of determining the amount of a substance A by using adding measured increments of substance B, the titrant, with which it reacts till precise chemical equivalence is completed the equivalence factor.
Learn more about titration here:-brainly.com/question/186765
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Answer:
The mass of I₂ produced is 66.43 g.
Explanation:
In a stoichiometry exercise we follow a series of steps.
Step 1: Write the balanced equation
2 CuCl₂ + 4 KI ⇄ 2 CuI + 4 KCl + I₂
Step 2: Look for the relationship between the data we have and the one we are looking for
According to the balanced equation, when 2 moles of CuCl₂ react 1 mole of I₂ is formed. This is the first relation. Secondly, we know that the molar mass of 253.80 g/mol, that is, every mole of I₂ has a mass of 253.80 g. This is the second relation.
Step 3: Apply relations to the data we have
