The answer is a. <span>It represents a linear function because there is a constant rate of change. This can be done the opposite way, but lets use minutes as x and hours as y. Every time y increases by 1, x increases by 60. This means there is a constant rate of change of 1 (rise) over 60 (run). A linear equation must have a constant rate of change.</span>
The measure of the angle formed by 2 chords that intersect inside the circle is 1/2<span> the sum of the chords' intercepted arcs.
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(83 + x)/2 = 107
83 + x = 107 * 2
83 + x = 214
x = 214 - 83
x = 131°
Answer:
The growth rate is 0.6
The growth factor is 1.6
Step-by-step explanation:
Generally, the exponential equation can be written as;
y = a(1 + r)^x
Where a is the initial value of 100
r is the growth rate
So let us form equations;
160 = 100(1 + r)^1 •••••(i)
Also;
256 = 100(1 + r)^2 •••••••(ii)
Divide equation ii by i
256/160 = 1 + r
1.6 = 1 + r
r = 1.6-1
r = 0.6
Answer:
Volume: 52 Units Squared
Surface Area: 94 units.
Step-by-step explanation:
The volume is relatively simple to find. Just subtract the original volume by the 2x2x2 cube's volume. The original volume is 60. The cube's volume is 2x2x2 which is 8. 60-8=52.
The surface area is harder to find. Try to envision the corner of the rectangle being cut out. We see that each side of the cube has a surface area of 2x2 which is 4. In the picture, we see that three sides of the rectangle has been partially removed. But since each side of the cube has an equal surface area, it is safe to minus 3 of the sides that has been partially removed by 3. However, since that it is the corner, the "dent" that the cube made in the rectangle also needed to be counted. As we said, each of the sides of a cube has a surface area of 4, so since that the dent has 3 sides, we see that the surface area of the dent is 4x3 which is 12. Now we need to count the unaffected sides of the rectangle. There are three of them. Just multiply the edges to find the surface area of each side. Add all of the values up: 11+16+12+8+15+12+20=94 units.
