All categories

3 years ago

Solve x + 3y = 9 3x – 3y = -13

Mathematics

2 answers:

Vedmedyk [2.9K]3 years ago

6 0

Answer:

x = -1

y = 3.33

Step-by-step explanation:

Isolate one term from either equation.

W'ell isolate x from the first equation.

x + 3y = 9

Rearrange:

x = 9 - 3y

Substitute this value for x into the second equation.

3x - 3y = -13

3(9 - 3y) -3y = -13

27 - 9y - 3y = -13

-12y = -40

y = 10/3 = 3.33

Substitute this value for y into the original equation.

x + 3 × (3.33) = 9

x = -1

Substitute both values into second equation to check.

3(-1) - 3(3.33) = -13

Therefore, x = -1

and y = 3.33 (or 10/3)

ss7ja [257]3 years ago

3 0

The answer is X= -1 and Y= 3.33

You might be interested in

What digit is in the ten thousands place 9,435,678

Maru [420]

Easy the 3 is in the ten thousands place

5 0

3 years ago

I need help on 11,12,13,14<br> plzzz help

Hatshy [7]

Answer:

555758439878392837290987394108734293028978439423389744983972493875824933289739829379398938297643589328975393894829798398379483979459384987853958046799358079989358u97y8976859967809084709-087090

Step-by-step explanation:

686959589588497878398689840938075u6654545

5 0

2 years ago

I need help right now this due today(you have been in this situation).

Free_Kalibri [48]

Answer:

7.62

Step-by-step explanation:

We can draw another point at (-3, -4) named C to get a right-angled triangle.

AC = 2 (by counting)

BC = 7 (by counting)

Using Pythagoras Theorem,

$AC^{2} +BC^{2} =AB^{2}$

$2^2+7^2=AB^2$

$4+49=AB^2$

$AB^2=58$

$AB=\sqrt{58} = 7.62$ (nearest hundredth)

8 0

3 years ago

How do you do polygons on coordinate grids

densk [106]

Answer:

When you do polygons on a coordinate grid, you will have points and then you connect them to form any type of polygon. There must be a total of 3 or more coordinate points.

5 0

3 years ago

(4x-9)(2x^2+2x+1) (4x−9)(2x 2 +2x+1)

tia_tia [17]

Answer:

$(4x-9)^2*(2x^2+2x+1)^2$

Step-by-step explanation:

(((4x-9)•(((2•(x2))+2x)+1))•(4x-9))•((2x2+2x)+1)

] (((4x-9)•((2x2+2x)+1))•(4x-9))•(2x2+2x+1)

Trying to factor by splitting the middle term

Factoring 2x2+2x+1

The first term is, 2x2 its coefficient is 2 .

The middle term is, +2x its coefficient is 2 .

The last term, "the constant", is +1

Step-1 : Multiply the coefficient of the first term by the constant 2 • 1 = 2

Step-2 : Find two factors of 2 whose sum equals the coefficient of the middle term, which is 2 .

-2 + -1 = -3

-1 + -2 = -3

1 + 2 = 3

2 + 1 = 3

Observation : No two such factors can be found !!

Conclusion : Trinomial can not be factored

((4x-9)•(2x2+2x+1)•(4x-9))•(2x2+2x+1)

Multiplying Exponential Expressions:

4.1 Multiply (4x-9) by (4x-9)

The rule says : To multiply exponential expressions which have the same base, add up their exponents.

In our case, the common base is (4x-9) and the exponents are :

1 , as (4x-9) is the same number as (4x-9)1

and 1 , as (4x-9) is the same number as (4x-9)1

The product is therefore, (4x-9)(1+1) = (4x-9)2

Trying to factor by splitting the middle term

5.1 Factoring 2x2+2x+1

The first term is, 2x2 its coefficient is 2 .

The middle term is, +2x its coefficient is 2 .

The last term, "the constant", is +1

Step-1 : Multiply the coefficient of the first term by the constant 2 • 1 = 2

Step-2 : Find two factors of 2 whose sum equals the coefficient of the middle term, which is 2 .

-2 + -1 = -3

-1 + -2 = -3

1 + 2 = 3

2 + 1 = 3

Observation : No two such factors can be found !!

Conclusion : Trinomial can not be factored

Multiplying Exponential Expressions:

5.2 Multiply (2x2+2x+1) by (2x2+2x+1)

The rule says : To multiply exponential expressions which have the same base, add up their exponents.

In our case, the common base is (2x2+2x+1) and the exponents are :

1 , as (2x2+2x+1) is the same number as (2x2+2x+1)1

and 1 , as (2x2+2x+1) is the same number as (2x2+2x+1)1

The product is therefore, (2x2+2x+1)(1+1) = (2x2+2x+1)2

Final result :

(4x - 9)2 • (2x2 + 2x + 1)2

6 0

2 years ago